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guajiro [1.7K]
3 years ago
10

An atom is always an element . but an element is not always an atom. but an element can also be a compound . an example is which

is an element and an atom while is an element and a molecule. a molecule is always made up of non-metals which are found to the right of the stairs on the ptoe. a molecule is always than one . but may be made up of or more the same elements or two or more elements. a molecule such as or are examples of molecules . molecules are always covalent bonds which are made up of . a compound is always than elements and must be made up of two types of elements. an example of a compound that is made of of non-metals is which can also be called a because it has more than one type of . an example of a compound that contains a metal is which is called a compound. formula units are always ionic bonds which means that they contain a . the difference between an atom and a molecule is the of elements in the formula. the difference between an element and a compound/formula is the of elements in the formula.
Chemistry
1 answer:
ivanzaharov [21]3 years ago
6 0
Non-metals is which can also be called a because it has more than one type of . an example of a compound
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Answer : The solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

Explanation :

First we have to calculate the concentration of solute.

\text{Concentration of solute}=\frac{Mass}{Volume}=\frac{4.51\times 10^{-3}g}{250mL}=1.80\times 10^{-5}g/mL

Now we have to calculate the Henry's law constant.

Using Henry's law :

C=k_H\times p

where,

C = concentration of solute = 1.80\times 10^{-5}g/mL

p = partial pressure = 27.59 kPa

k_H = Henry's law constant = ?

Now put all the given values in the above formula, we get:

1.80\times 10^{-5}g/mL=k_H\times (27.59kPa)

K_H=6.52\times 10^{-7}g/mL.kPa

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

C_{(79.39kPa)}=k_H\times p

C_{(79.39kPa)}=(6.52\times 10^{-7}g/mL.kPa)\times (79.39kPa)

C_{(79.39kPa)}=5.18\times 10^{-5}g/mL

Therefore, the solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

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