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3 years ago

The population of Jefferson City is 95000. Assuming a growth rate of 2.5% per year, what will the population be in 15 years?

Mathematics

1 answer:

Softa [21]3 years ago

3 0

Answer:

Yearly growth: 137,588

Continuous growth: 3,971,611

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Order of the set of numbers from least to greatest : Square root of 64, 8 1/7,8.14...,15/2 please help

KIM [24]

Answer:

15 /2 , Square root of 64, 8.14, 8 1/7

4 0

3 years ago

A man sold his house for $125,000. After paying he broker his commission, the man received $116,875. What was the broker’s commi

PilotLPTM [1.2K]

116875 = (x / 100) * 125000

116875 = x * 125000 / 100

116875 = 1250x (The zeros get cancelled)

Therefore, x = 116875/1250 = 187/2 = 93.5%

4 0

4 years ago

Use the properties of exponents to rewrite the expression. (-3yz)(-3yz)(-3yz)(-3yz)

Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0

3 years ago

Please help me with this all 2-18 while i do the rest of my work

AlexFokin [52]

Answer:

2.26 13.-8

3.-14 14.-1

4.-12 15.3

5.-15 16.-3

6.-5 17.8

7.-15 18.-20

8.-2

9.39

10.-125

11.-50

12.29

Step-by-step explanation:

Your welcome

7 0

3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago