Analyzing a blood sample usually involves which type of separation method?

the diagram below shows a segment of DNA before and after erplication, which of the following could have occured as a result of

Lorico [155]

The change or mutation in a segment of DNA after replication may lead to changes in the genotype, the traits of the organism and the proteins (option i, ii and iii).

<h3>What is a genetic mutation?</h3>

A genetic mutation is any change in the nucleotide bases of the genome of an organism that may be associated with modifications in the phenotypic traits or features of the organism if this change alters the expression of a given gene that produces a particular protein.

Mutations may be neutral when they don't show an apparent effect on the phenotype of an organism such as occur in mutations located in intergenic regions.

Therefore, with this data, we can see that a genetic mutation may alter the proteins produced by an organism which has a direct effect on the phenotype by altering the structures that it is able to synthesize.

Learn more about genetic mutations here:

brainly.com/question/29000870

#SPJ1

8 0

1 year ago

A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi

docker41 [41]

<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8 t = 4
s = 6*t^2 + 2*t s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>

6 0

3 years ago

I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b

viva [34]

Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, $P=hg\rho$

Where h is the height that water is to reach, g is gravitational constant and $\rho$ is the density, in this case, we assume $\rho$ of pure water as $1000 Kg/m^3$

Assuming $g=10 m/s^{2}$

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

$P=0.5v^{2}\rho$ where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

$P=0.5v^{2}\rho=hg\rho$

Notice that $\rho$ is common hence

$0.5v^{2}=hg$

Making V the subject of the formula

$v^{2}=2hg$

$v=\sqrt 2hg$

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

$v=\sqrt 2*10*6.4=11.3137085 m/s$

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

$v=\sqrt 2hg$

Taking g as 9.8 and h now is 8m

$v=\sqrt 2*8*9.8$

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

6 0

3 years ago

Two children, Ferdinand and Isabella, are playing with a waterhose on a sunny summer day. Isabella is holding the hose in herhan

sweet [91]

Answer:

84.196%

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

$y_0=1\ m$

x = 10 m

t = Time taken

$v_0$ = 3.5 m/s (assumed, as it is not given)

$A_0$ = $\pi 1.5^2$

We have the equation

$y=y_0+ut+\dfrac{1}{2}gt^2\\\Rightarrow 0=y_0-\dfrac{1}{2}gt^2\\\Rightarrow t=\sqrt{\dfrac{2y_0}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1}{9.81}}\\\Rightarrow t=0.45152\ s$