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3 years ago

What is an Advantage and Dis Advantage of energy?

Physics

2 answers:

kifflom [539]3 years ago

5 0

Answer:

Advantage and Dis Advantage of energy is discussed below.

Explanation:

Advantage of Energy

Environmental and commercial advantages of using renewable energy incorporate: Producing energy that creates no greenhouse gas discharges from relic fuels and diminishes some kinds of air pollution.

Disadvantage of Energy

Higher upfront price. While you can conserve bills by using renewable energy, the technologies are typically more costly upfront than conventional energy dynamos.

Inga [223]3 years ago

4 0

The more energy you have the more things you might be able to do but it may be problematic when trying to go to sleep or trying to calm down, believe me, I know.

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A research assistant in a lab conditions dogs to salivate to the sound of a bell. During conditioning, the assistant deliberatel

sattari [20]

Answer:

D. independent; dependent

Explanation:

The dependent variable is the variable that is being measured during the course of an experiment. It represents the variable that changes with the manipulation of other variables.

The independent variables are variables which are varied or manipulated during the course of an experiment. The effects of their variations are measured on the dependent variable.

<em>In this case, the interval between the bell and presentation of food was varied and the effects of the variation was measured by determining the amount of salivation.</em>

Hence, the interval is the independent variable and the amount of salivation is the dependent variable.

The correct option is D.

5 0

3 years ago

A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −

romanna [79]

Answer:

The speed of electron is $1.5\times10^{7}\ m/s$

Explanation:

Given that,

Electric field $E=1.50\times10^{3}\ N/C$

Distance = -0.0200

The electron's speed has fallen by half when it reaches x = 0.190 m.

Potential energy $P.E=5.04\times10^{-17}\ J$

Change in potential energy $\Delta P.E=-9.60\times10^{-17}\ J$ as it goes x = 0.190 m to x = -0.210 m

We need to calculate the work done by the electric field

Using formula of work done

$W=-eE\Delta x$

Put the value into the formula

$W=-1.6\times10^{-19}\times1.50\times10^{3}\times(0.190-(-0.0200))$

$W=-5.04\times10^{-17}\ J$

We need to calculate the initial velocity

Using change in kinetic energy,

$\Delta K.E = \dfrac{1}{2}m(\dfrac{v}{2})^2+\dfrac{1}{2}mv^2$

$\Delta K.E=\dfrac{-3mv^2}{8}$

Now, using work energy theorem

$\Delta K.E=W$

$\Delta K.E=\Delta U$

So, $\Delta U=W$

Put the value in the equation

$\dfrac{-3mv^2}{8}=-5.04\times10^{-17}$

$v^2=\dfrac{8\times(5.04\times10^{-17})}{3m}$

Put the value of m

$v=\sqrt{\dfrac{8\times(5.04\times10^{-17})}{3\times9.1\times10^{-31}}}$

$v=1.21\times10^{7}\ m/s$

We need to calculate the change in potential energy

Using given potential energy

$\Delta U=-9.60\times10^{-17}-(-5.04\times10^{-17})$

$\Delta U=-4.56\times10^{-17}\ J$

We need to calculate the speed of electron

Using change in energy

$\Delta U=-W=-\Delta K.E$

$\Delta K.E=\Delta U$

$\dfrac{1}{2}m(v_{f}^2-v_{i}^2)=4.56\times10^{-17}$

Put the value into the formula

$v_{f}=\sqrt{\dfrac{2\times4.56\times10^{-17}}{9.1\times10^{-31}}+(1.21\times10^{7})^2}$

$v_{f}=1.5\times10^{7}\ m/s$

Hence, The speed of electron is $1.5\times10^{7}\ m/s$

4 0

3 years ago

A duck is 12 m from the edge of a pond. A student stands in the middle of the pond

olganol [36]

Answer:

The wavelength is 2 meters

Explanation:

The relationship between the frequency, the speed and the wavelength is given by the relation;

v = f × λ

The given parameters are;

The distance of the duck from the edge of the pond = 12 m

The number of ripples produced per second = Frequency, f = 2 Hz

The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds

Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s

The wavelength, λ, is therefore;

λ = v/f = (4 m/s)/(2 Hz) = 2 meters.

6 0

3 years ago

A very small tilt in Earth’s axis would likely cause ____.

olchik [2.2K]

If the Earth's axis were closer to "straight up and down" than
the present 23.5°, then . . .

-- The areas around the north and south poles where the sun
can be up or down for more than 24 hours would be smaller.

-- The "Tropic Zone", between the Tropic of Cancer and the
Tropic of Capricorn, where it's possible for the sun to be
directly overhead, would be narrower.

-- There would be less difference, everywhere, between the
lengths of daylight on the "longest day" and the "shortest day"
of the year.

-- The seasons would be less extreme everywhere. There would
be less difference, everywhere, between the coldest part of the
Winter and the warmest part of the Summer.

3 0

4 years ago

Read 2 more answers

If a book is knocked off a desk that is .75 m tall at a rate of 2.0 m/s, how far away from the desk does it fall

ANEK [815]

Answer: 0.8 m

Explanation:

In the vertical direction, the speed is zero, u = 0.

Distance covered in the vertical direction, s = 0.75 m.

The book would fall with acceleration due to gravity in the vertical direction, a = g = 9.8 m/s²

From the equation of motion,

s = u t + 0.5 a t²

Substituting the above values, we will find out the time taken for the book to hit the ground.

⇒0.75 m=0+0.5×9.8 m/s²×t²

⇒t = √0.153 = 0.39 s ≈ 0.40 s

Now, the horizontal distance covered,

d = v×t ⇒d= 2.0 m/s × 0.40 s =0.8 m

Hence, the book falls 0.8 m away from the desk.

7 0

3 years ago