To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as
F = ma
Where,
m= Mass
a = Acceleration
At the same time the frictional force can be defined as,

Where,
 Frictional coefficient
 Frictional coefficient
N = Normal force (mass*gravity)
Our values are given as,

By condition of Balance the friction force must be equal to the total net force, that is to say



Re-arrange to find acceleration,



Therefore the acceleration the horse can give is 
 
        
             
        
        
        
Answer:

Explanation:
Since fluid is pumping in and out at the same rate (5L/min), the total fluid volume in the tank stays constant at 350L. Only the amount of salt and its concentration changed overtime.
Let A(t) be the amount of salt (g) at time t and C(t) (g/L) be the concentration at time t
A(0) = 10 g
Brine with concentration of 1g/L is pouring in at the rate of 5L/min so the salt income rate is 5 g/min
The well-mixed solution is pouring out at the rate of 5L/min at concentration C(t) so the salt outcome rate is 5C g/min
But the concentration is total amount of salt over 350L constant volume
C = A / 350
Therefore our rate of change for salt A' is
A' = 5 - 5A/350 = 5 - A/70
This is a first-order linear ordinary differential equation and it has the form of y' = a + by. The solution of this is

So 
with A(0) = 10
c + 350 = 10
c = 10 - 350 = -340

 
        
             
        
        
        
Answer:  
 
Explanation:
We are given the following formula:
 (1)
   (1)
Where:
 is the amount of heat
 is the amount of heat
 is the mass  of water
  is the mass  of water
 is the specific heat of water
  is the specific heat of water
 is the variation in temperature, which in this case is
  is the variation in temperature, which in this case is   
  
Rewriting equation (1) with the known values at the right side, we will prove the result is  :
:
 (2)
   (2)
 This is the result
   This is the result
 
        
             
        
        
        
 Answer:
The 16ᵗʰ term of this sequence is 82
Step-by-step explanation:
Here, 
First Term = a₁ = 9
Common Difference = (d) = 2
Now, For 16ᵗʰ term, n = 16
<em>aₙ = a + (n - 1)d</em>
a₁₆ = 7 + (16 - 1) × 2
a₁₆ = 7 + 15 × 5
a₁₆ = 7 + 75
a₁₆ = 82
Thus, The 16ᵗʰ term of this sequence is 82
<u>-TheUnknownScientist</u>
 
        
             
        
        
        
Answer:
The value of A is 1.5m/s^2 and B is 0.5m/s^³
Explanation:
The mass of the rocket = 2540 kg.
Given velocity, v(t)=At + Bt^2
Given t =0  
a= 1.50 m/s^2
Now, velocity V(t) = A*t + B*t²
If,  V(0) = 0, V(1) = 2
a(t) = dV/dt = A+2B × t  
a(0) = 1.5m/s^²  
1.5m/s^²  =  A + 2B ×  0  
A = 1.5m/s^2
now,
V(1) = 2 = A× 1 + B× 1^²  
 1.5× 1 +B× 1 = 2m/s
B = 2-1.5  
B = 0.5m/s^³
Now Check V(t) = A× t + B × t^²
So, V(1) = A× (1s) + B× (1s)^² = 1.5m/s^² ×  1s + 0.5m/s^³ × (1s)^² = 1.5m/s + 0.5m/s = 2m/s  
Therefore, B is having a unit of m/s^³ so B× (1s)^² has units of velocity (m/s)