Answer:
the answer is 1, oil and water
Answer:
Part a)
![E = \frac{8.60}{2.62} = 3.28 J](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B8.60%7D%7B2.62%7D%20%3D%203.28%20J)
Part b)
![E = 2.62(8.60) = 22.5 J](https://tex.z-dn.net/?f=E%20%3D%202.62%288.60%29%20%3D%2022.5%20J)
Explanation:
As we know that the energy of capacitor when it is not connected to potential source is given as
![U = \frac{Q^2}{2C}](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7BQ%5E2%7D%7B2C%7D)
As we know that initial energy is given as
![8.60 = \frac{Q^2}{2C}](https://tex.z-dn.net/?f=8.60%20%3D%20%5Cfrac%7BQ%5E2%7D%7B2C%7D)
now we know that capacitance of parallel plate capacitor is given as
![C = \frac{\epsilon_0A}{d}](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7B%5Cepsilon_0A%7D%7Bd%7D)
now the new capacitance when distance is changed from 3.80 mm to 1.45 mm
![C' = \frac{Cd}{d'}](https://tex.z-dn.net/?f=C%27%20%3D%20%5Cfrac%7BCd%7D%7Bd%27%7D)
![C' = \frac{C(3.80)}{1.45}](https://tex.z-dn.net/?f=C%27%20%3D%20%5Cfrac%7BC%283.80%29%7D%7B1.45%7D)
![C' = 2.62 C](https://tex.z-dn.net/?f=C%27%20%3D%202.62%20C)
Now the new energy of the capacitor is given as
![E = \frac{Q^2}{2(2.62C)}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BQ%5E2%7D%7B2%282.62C%29%7D)
![E = \frac{8.60}{2.62} = 3.28 J](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B8.60%7D%7B2.62%7D%20%3D%203.28%20J)
Part b)
Now if the voltage difference between the plates of capacitor is given constant
now the energy energy of capacitor is
![U = \frac{1}{2}CV^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cfrac%7B1%7D%7B2%7DCV%5E2)
![8.60 = \frac{1}{2}CV^2](https://tex.z-dn.net/?f=8.60%20%3D%20%5Cfrac%7B1%7D%7B2%7DCV%5E2)
now when capacitance is changed to new value then new energy is given as
![E = \frac{1}{2}C'V^2](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7DC%27V%5E2)
![E = \frac{1}{2}(2.62C)V^2](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%282.62C%29V%5E2)
![E = 2.62(8.60) = 22.5 J](https://tex.z-dn.net/?f=E%20%3D%202.62%288.60%29%20%3D%2022.5%20J)
How do fission nuclear reactions differ from fusion nuclear reactions?
A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not.
B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not.
C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.
D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.
Answer:
C
Explanation:
Both fission and fusion are nuclear reactions that produce energy, but their applications differs.
Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.
The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.
The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.
D. an outside or unbalanced force acts upon the object.