I believe it is Acoustics, the real name for it would be like Reverberation. But go with Acoustics. :)
Answer:
h2 = 0.092m
Explanation:
From a balance of energy from point A to point B, we get speed before the collision:
Solving for Vb:

Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:

Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:
Solving for h2:
h2 = 0.092m
True: Friction depends on the types of surfaces involved and how hard the surfaces push together.
Answer:
Fc = 19.2 N
Explanation:
In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

m: mass of the rock = 600g = 0.6 kg
v: tangential velocity of the Honda = 4m/s
r: radius of the Honda = 50cm = 0.5m
You replace the values of m, r and v in the equation for Fc:

hence, the force has a magnitude of 19.2 N
If the rock would have more mass the centripetal force would be higher