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Hunter-Best [27]
3 years ago
6

When a guitar string is plucked, sound waves, which are mechanical waves, transmit sound to your ears. What is the primary mediu

m through which the sound waves travel?
Physics
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

jjjjj

Explanation:

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A boy of mass 50 kg exerts a pressure of 25000 pa calculate the area
gtnhenbr [62]

Answer: A = 0.02 m²

Explanation: Solution:

Pressure is expressed in the formula:

P = F / A       where F = mg

  = mg /A

  = 50 kg ( 9.8 m/s²) / 25000 Pa

  =  0.02 m²

3 0
3 years ago
What is the distance a bullet will travel when launched at 166 meters per second for 5.75seconds?
vodka [1.7K]
166x5.75= 954.5 meters in 5.75 seconds.
3 0
3 years ago
Alicia drew a pentagon with equal side length and equal angles.Then she added red lines of symmetry to her drawing. How many lin
IRISSAK [1]
The sum of angles in a regular pentagon is
180*(5 - 2) = 540°
Each internal angle is 540/5 = 108°.

Each vertex creates a line of symmetry to the midpoint of the opposite side,
as shown in the figure.

Answer: 5 lines of symmetry.

7 0
3 years ago
A 15-µF capacitor is charged to 40 V and then connected across an initially uncharged 25-µF capacitor. What is the final potenti
Kobotan [32]

Answer:

24volts

Explanation:

If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;

Q = CV where;

Q is the charge flowing across the capacitor

C is the capacitance of the capacitor. = 15-µF

V is the voltage = 40V

Q = 15×10^-6×40

Q = 0.0006coulombs

If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;

Q = CV

V = Q/C

V = 0.0006/25×10^-6

V = 24Volts

Therefore, the final potential difference across the 25-µF capacitor will be 24volts

6 0
3 years ago
Read 2 more answers
A 56.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.517 and 0.260,
kifflom [539]

Answer:

Explanation:

Magnitude of frictional force = μ mg

μ is either static or kinetic friction.

To start the crate moving , static friction is calculated .

a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .

force required =.517 x 56.6  x 9.8 = 286.76  N .

b ) to  slide the crate across the dock at a constant speed , force required

= μ mg where μ is coefficient of kinetic  friction , where μ is kinetic friction

= .26 x 56.6  x 9.8 = 144.21 N .

3 0
3 years ago
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