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tekilochka [14]

3 years ago

5

Cut out a piece of cardboard in the shape of a letter C and locate the center of mass. is it within the frame of the letter? Can

it be balanced at the center of mass? Yes or no. Explain.

1 answer:

Mice21 [21]3 years ago

3 0

Answer:

No

Explanation:

Because the mass of the object on the sides are not filled in a way to be able to find the center of the mass.

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A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between

Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

Initial speed = 5.49 m/s

Coefficient of kinetic friction = 0.229

Distance = 3.89 m

We need to calculate the acceleration of sled

Using formula of acceleration

$a = \dfrac{F}{m}$

Where, F = frictional force

m = mass

Put the value into the formula

$a=\dfrac{\mu mg}{m}$

$a=\mu g$

$a=0.229\times9.8$

$a=2.244\ m/s^2$

We need to calculate the speed of the sled

Using equation of motion

$v^2=u^2-2as$

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value in the equation

$v ^2=(5.49)^2-2\times2.244\times3.89$

$v=\sqrt{(5.49)^2-2\times2.244\times3.89}$

$v=3.56\ m/s$

Hence, The speed of the sled is 3.56 m/s.

8 0

3 years ago

What is the equivalent resistance of the circuit?

raketka [301]

Answer:

I feel it would be D. 120.00 I'm really not sure

Explanation:

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3 years ago

If an insulator replaces a conductor in an electrical circuit, the flow of electrons in the circuit will be

Degger [83]

The flow of electrons in the circuit will be less.

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3 years ago

your friend sit in a sked in the snow. if you apply a force of 120 N to them, they have an acceleration of 1.3 m/s2. what is the

levacccp [35]

Need to know the equation for force
F=MA
F is force
M is mass- we need to know the mass
A is acceleration
use "x" for mass
120 N= 1.3x
divide 1.3 in both side
kg unit for mass
X=92.31 kg
or
mass = 92.31 kg
Hope this helps

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3 years ago

Which planet was almost massive enough to have become a star?

ololo11 [35]

Jupiter ............................................

3 0

2 years ago

Read 2 more answers