Balance chemical equation NaNO3=>NaNO2+O2

A ball is thrown downward at 5ms from roof 10m high its velocity when it reaches the ground is?,

lions [1.4K]

<span>A ball is thrown downward at 5ms from roof 10m high its velocity when it reaches the ground is 0 m/s. This is because it already dropped from the ground or x axis. So the velocity already stopped. </span>

5 0

4 years ago

A 200.0 g block rests on a frictionless, horizontal surface. It is pressed against a horizontal spring with spring constant 4500

kenny6666 [7]

Answer:

6 m/s

Explanation:

Given that :

mass of the block m = 200.0 g = 200 × 10⁻³ kg

the horizontal spring constant k = 4500.0 N/m

position of the block (distance x) = 4.00 cm = 0.04 m

To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.

i.e $\frac{1}{2} kx^2 = \frac{1}{2} mv^2$

$kx^2 = mv^2$

$4500* 0.04^2 = 200*10^{-3} *v^2$

$7.2 =200*10^{-3}*v^{2}$

$v^{2} =\frac{7.2}{200*10^{-3}}$

$v =\sqrt{\frac{7.2}{200*10^{-3}}}$

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is 6 m/s

5 0

4 years ago

A pump is used to lift 100 KG of water from a wel 60 m deep,in 20 S If force of gravity on 1 KG is 10 N,find

Harlamova29_29 [7]

Explanation:

Given,

m = 100 kg
g = 10 N/kg¹
h = 60 m
t = 20 s

To Find:

a) Work done by the pump

b) Potential energy stored in the water

c)Power spent by the pump

d)Power rating of the pump.

Solution:

a) Work done by the pump

We know that,

$\rm \: Work \: done = Force * Distance \: moved$

f = 100 kg * 10N/kg
d = 60 m

$\rm \: Work\; Done =(100 \: kg \times \cfrac{10N}{kg} ) \times 60 \: m$

$\rm \: Work\; Done =1000 \times 60 \: joule$

$\boxed{\rm \: Work\; Done =60000 \: joule}$

[The unit'll be joule since N×M = J]

b) Potential energy stored in the water

$\rm \: P.E = m \cdot g \cdot h$

m = 100 kg
g = 10N/kg
h = 60

$\rm \: P.E =100 \:kg \: \times \cfrac{10 \: N}{kg} \times 60$

$\boxed{\rm \: P.E =60000 \: joule}$

same condition here as well, N×M = J
c) Power of the Pump

$\rm \: P = W/T$

where P = Power; W = Work done & T = Time taken
As we got the value of work done on question (a),& ATQ time taken is 20 S.

$\rm \: P = \cfrac{60000 \: joule}{20 \: seconds} =\boxed{\rm { 3000 \: Watts }}\: or \: \boxed{\rm 3 \: kW}$

d) Power rating of the pump = 3 kW

Assumption: The pump is 100% efficient & works well.

6 0

2 years ago

Drag the positive or negative feedback loop on the left to each process on the right. terms may be used once, more than once, or

slamgirl [31]

The order of the positive and negative feedback loops are positive, positive, negative, positive, positive, negative.

<h3>What is a feedback loop?</h3>

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent actions. A minimum of four phases comprise each feedback loop. Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for sustaining an ideal condition. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

To learn more about feedback loop, visit:

brainly.com/question/11312580

#SPJ4

5 0

2 years ago

People can stay informed of weather events by listening to weather updates on the radio. True or False

Cloud [144]

Answer:

the answer is true

Explanation:

true

6 0

4 years ago

Read 2 more answers