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3 years ago

According to Galileo's pendulum theory, which factor determines the time taken to swing through one complete cycle?

2 answers:

6 0

It depends on the length of the string and the speed its swinging at. If its short then it will reach the full swing in less of a time but if its a longer string then it would take a longer time to make a full swing.

lora16 [44]3 years ago

5 0

Explanation :

The time period of the Galileo's pendulum is given by :

$T=2\pi\sqrt{\dfrac{L}{g}}$

Where,

L is the length of the pendulum

g is acceleration due to gravity

So, the time period of the depends on the length of the pendulum. It is independent of the mass of the bob and its amplitude.

So, the length is the only factor that determines the time taken to swing through one complete cycle is the length of the pendulum.

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A particle moves along the x-axis according to x(t)=10t−2t²m. (a) What is the instantaneous velocity at t = 2 s and t = 3 s? (b)

Alisiya [41]

Answer:

a) v(2) = 2m/s, v(3) = -2m/s

b) speed at t = 2s is 2m/s

speed at t = 3s is 2m/s

c) 0 m/s

Explanation:

We can take the derivative of x(t) to find the equation of velocity

v(t) = x'(t) = 10 - 4t

(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s

v(3) = 10 - 4*3 = 10 - 12 = -2 m/s

(b) The speed would be the same as velocity without the direction

speed at t = 2s is 2m/s

speed at t = 3s is 2m/s

$v_a = \frac{s(3) - s(2)}{\Delta t} = \frac{10*3 - 2*3^2 - (10*2 - 2*2^2)}{3 - 2}$

$v_a = \frac{12 - 12}{1} = 0/1 = 0 m/s$

6 0

3 years ago

9. During an egg toss, a catcher must cushion the egg by maximizing the time it takes to stop the

Lorico [155]

Answer:

the impulse experienced by the egg is 0.053 kgm/s.

Explanation:

Given;

mass of the egg, m = 60 g = 0.06 kg

initial velocity of the egg, u = 6 m/s

height moved by the egg, h = 50 cm = 0.5 m

Determine the final velocity of the egg as it moves upward;

v² = u² + 2(-g)h

v² = u² - 2gh

where;

v is the final velocity

-g is negative acceleration due gravity as it moves upward

v² = 6² - 2(9.8 x 0.5)

v² = 26.2

v = √26.2

v = 5.12 m/s

The impulse applied to the egg is the change in linear momentum;

J = ΔP

ΔP = mu - mv

ΔP = m(u - v)

ΔP = 0.06(6 - 5.12)

ΔP = 0.053 kgm/s

Therefore, the impulse experienced by the egg is 0.053 kgm/s.

8 0

3 years ago

a resistor, of resistance 47 , is damaged when it dissipates a power greater than 0.5W. determine the maximum voltage that can b

harkovskaia [24]

Answer:

<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>

Explanation:

<u>Electric Power in a Resistor</u>

Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:

V = R.I

The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:

$P = I^2.R$

Solving the first equation for I:

$\displaystyle I=\frac{V}{R}$

Substituting in the second equation:

$\displaystyle P=\frac{V^2}{R^2}.R$

Simplifying:

$\displaystyle P=\frac{V^2}{R}$

Solving for V:

$V=\sqrt{P.R}$

The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:

$V=\sqrt{0.5\cdot 47}$

$V=\sqrt{23.5}$

V = 4.85 V

The maximum voltage that can be applied without damaging the resistor is 4.85 V

6 0

3 years ago

Now imagine a person dragging a 50 kg box along the ground with a rope, as

ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

= 50 x 9.8

= 490 N

The coefficient of friction,

μ = f/ η

= 30 / 490

= 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0

4 years ago

A circut contains a 2 microfarads and a 20 microfarads capacitor connected in parallel. What is the total capacitance of the cir

garik1379 [7]

The answer to this question would be:C. 22mf

In this question, there are two capacitors that connected in parallel. The formula to count the capacitor is the opposite of the formula used for the resistor. If constructed in series, the capacitor will have reduced capacitance. For parallel condition the equation would be:

Ctotal= C1+C2
C total= 2 mf+ 20mf= 22mf

5 0

4 years ago