Answer:
basically I will tell you the definition
Explanation:
so when charges are unbalanced statistic energy is formed positive attract negative and negative attracts positive like repell while unlike attract .
My personal understanding and opinion is that ALL of those questions
should be part of an assessment of Physical Activity Readiness.
Answer:
3 seconds
Explanation:
Applying,
Applying,
v = u±gt................ Equation 1
Where v = final velocity, u = initial velocity, t = time, g = acceleration due to gravity.
From the question,
Given: v = 0 m/s ( at the maximum height), u = 30 m/s
Constant: g = -10 m/s
Substitute these values into equation 1
0 = 30-10t
10t = 30
t = 30/10
t = 3 seconds
Answer:
E=
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by

Substitute x=a and R=a
Then, we get




Where K=
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=
intensity of a star is inversely depends on the square of the distance from the star
we can say it is given as

here we know that

also we know that

now we will have



so other star is at distance 60 Light years