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goldfiish [28.3K]
2 years ago
7

Drag the positive or negative feedback loop on the left to each process on the right. terms may be used once, more than once, or

not at all.
Physics
1 answer:
slamgirl [31]2 years ago
5 0

The order of the positive and negative feedback loops are positive, positive, negative, positive, positive, negative.

<h3>What is a feedback loop?</h3>

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent actions. A minimum of four phases comprise each feedback loop. Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for sustaining an ideal condition. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

To learn more about feedback loop, visit:

brainly.com/question/11312580

#SPJ4

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A driver dices off of a diving board 25 meter high. If he dives with a initial velocity of -1.2m/s and his acceleration is -9.8
kifflom [539]

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3 0
4 years ago
An 18 gauge copper wire (the size usually used for lamp cords), with a diameter of 1.02 mm,1.02 mm, carries a constant current o
larisa86 [58]

Answer:

J = 2.044x10⁶ A/m²

v = 1.50x10⁻⁴ m/s

Explanation:  

The current density (J) of the copper wire is giving by:  

J = \frac {I}{A}

<em>where I: electric current and A: cross-sectional area of the copper wire</em>

<u>The cross-sectional area of the copper wire can be calculated by:</u>

A = \frac {\pi d^{2}}{4} = \frac {\pi (1.02 \cdot 10^{-3} m)^{2}}{4} = 8.17 \cdot 10^{-07} m^{2}         

<u>Substituting the calculated area in the equation (1) we have:</u>

J = \frac {1.67 A}{8.17 \cdot 10^{-7} m^{2}} = 2.044 \cdot 10^{6} \frac {A}{m^{2}}    

Hence, the current density is 2.044x10⁶ A/m².    

To find the drift speed (v), we need to use the next equation:

v = \frac {J}{n q}  

<em>where n: the free-electron density, q: module of the charge of the electron </em>

v = \frac {2.044 \cdot 10^{6} \frac {A}{m^{2}}}{(8.5 \cdot 10^{28} {m^{-3}}) (1.6 \cdot 10^{-19} C)}  

v = 1.50 \cdot 10^{-04} \frac {m}{s}                            

So, the drift speed is 1.50x10⁻⁴ m/s.

Have a nice day!    

4 0
4 years ago
Read 2 more answers
_____is the most abused of all fossil fuels <br> A.Gasoline<br> B.Coal<br> CPeat<br> D petroleum
Kisachek [45]
Coal is the answer to the question


3 0
3 years ago
for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​
Ilia_Sergeevich [38]

Answer:

O²⁻

Explanation:

Number of protons  = 8

Number of neutrons  = 9

Number of electrons  = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

 For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

     Charge  = Number of protons  - Number of electrons

      Charge  =  8  - 10  = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

 The ion is O²⁻

8 0
3 years ago
In the fabrication of an electrical extension cord, the manufacturer wants to reduce the overall resistance of the wires in the
Bezzdna [24]

Answer:

Option B is correct.

Explanation:

The resistance of a material or wire is represented by the formula below.

R=(ρL)/A

where

  • R is resistance of wire
  • ρ is the resistivity of the material
  • A is the cross sectional area of wire
  • L is length of wire

Resistance increases with increase in length and resistivity which means options C and D are wrong.

A=(πd^{2})/4

An increase in diameter will result in a proportional increase in area

From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct

Have a great day

5 0
3 years ago
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