Answer:
J = 2.044x10⁶ A/m²
v = 1.50x10⁻⁴ m/s
Explanation:
The current density (J) of the copper wire is giving by:

<em>where I: electric current and A: cross-sectional area of the copper wire</em>
<u>The cross-sectional area of the copper wire can be calculated by:</u>
<u>Substituting the calculated area in the equation (1) we have:</u>
Hence, the current density is 2.044x10⁶ A/m².
To find the drift speed (v), we need to use the next equation:
<em>where n: the free-electron density, q: module of the charge of the electron </em>
So, the drift speed is 1.50x10⁻⁴ m/s.
Have a nice day!
Coal is the answer to the question
Answer:
O²⁻
Explanation:
Number of protons = 8
Number of neutrons = 9
Number of electrons = 10
What type of atom or ion is it = ?
Solution:
Protons are the positively charged particle in an atom
Neutrons do not carry any charges
Electrons are negatively charged particles
For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.
Now,
Charge = Number of protons - Number of electrons
Charge = 8 - 10 = -2
The charge on the atom is -2 and so it is an oxygen ion with -2 charge
The ion is O²⁻
Answer:
Option B is correct.
Explanation:
The resistance of a material or wire is represented by the formula below.
R=(ρL)/A
where
- R is resistance of wire
- ρ is the resistivity of the material
- A is the cross sectional area of wire
- L is length of wire
Resistance increases with increase in length and resistivity which means options C and D are wrong.
A=(π
)/4
An increase in diameter will result in a proportional increase in area
From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct
Have a great day