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andre [41]
3 years ago
13

A dog ran 10 meters in 2 seconds. What was the dog's speed? (Use the

Physics
2 answers:
zaharov [31]3 years ago
5 0
The answer is c. 5m/s! why can i get be like marked
Nina [5.8K]3 years ago
3 0

Answer:

C 5 m/2

M stands for meters and S stands for seconds

We can do 10/2 which makes 5.

The answer is 5 m/2

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Question 7 (4 points) (01.02 MC) The gravitational strength at the poles is greater than the gravitational strength at the equat
musickatia [10]
I think it’s A but not really sure
4 0
4 years ago
URGENT
Gemiola [76]

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

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7 0
3 years ago
Can you please help me with this physics question
erastova [34]

Answer:

See the answers below

Explanation:

We can solve both problems using vector sum.

a)

Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative

F_{resultant}=100+30-85+900\\F_{resultant}=845[N]

The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.

F_{drag}=50[N]

b)

Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.

F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN]

6 0
3 years ago
In a car lift, compressed air exerts a force on a piston with a radius of 2.62 cm. This pressure is transmitted to a second pist
marin [14]

Answer:

847.45 N

Explanation:

F₁=force of exerted by smaller piston

F₂=force of exerted by larger piston=1.44×10⁴ N

A₁=Area of smaller piston= 2.62 cm =0.0265 m

A₂=Area of larger piston= 10.8 cm =0.108 m

Pressure exerted by both the pistons will be equal

P_1=P_2\\\Rightarrow \frac{F_1}{A_1}=\frac{F_2}{A_2}\\\Rightarrow F_1=\frac{F_2}{A_2} A_1\\\Rightarrow F_1=\frac{14400}{\pi\times  0.108^2}\pi\times  0.0262^2\\\Rightarrow F_1=847.45\ N

Hence, force exerted to lift a 14400 N car is 847.45 N

8 0
4 years ago
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