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sp2606 [1]
3 years ago
14

What force holds the lattice structure in place in a crystal?

Physics
2 answers:
Arada [10]3 years ago
4 0
At the end it depends on the type of crystal.

There are ionic crystals (like sodium chloride), covalent cristals (like diamond) and metallic crystals (like aluminum).

The context of the question may tell you if it is referred to one type of crystal or other.

I gues it may be about salt compounds, which are ionic crystals. In this case, the force that holds the lattice structure in place in a crystal is ionic (electrical attraction between cations and anions).

In the other two cases, the force is covalent bond in one case and metallic bond in the other case.
MAXImum [283]3 years ago
3 0

The attraction between ions of opposite charge.

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Compute the torque about the origin of the gravitational force F--mgj acting on a particle of mass m located at 7-xî+ yj and sho
Andrews [41]

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Explanation:

Force, F = - mg j

r = - 7x i + y j

Torque is defined as the product f force and the perpendicular distance.

It is also defined as the cross product of force vector and the displacement vector.

\overrightarrow{\tau }=\overrightarrow{r}\times \overrightarrow{F}

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3 0
3 years ago
A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
AysviL [449]

Answer:

2.28

Explanation:

From mirror formula,

1/f = 1/u+1/v .......... Equation 1

Where f = focal length of the mirror, v = image distance, u = object distance.

Note: The focal length mirror is positive.

make v the subject of the equation,

v = fu/(u-f)............ Equation 2

Given: f = 2.5 cm, u = 1.4 cm

Substitute into equation 2

v = 2.5(1.4)/(1.4-2.5)

v = 3.5/-1.1

v = -3.2 cm.

Note: v is negative because it is a virtual image.

But,

Magnification = image distance/object distance

M = v/u

Where M = magnification.

Given: v = 3.2 cm, u = 1.4 cm

M = 3.2/1.4

M = 2.28.

Thus the magnification of the tooth = 2.28.

3 0
4 years ago
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