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Firlakuza [10]
3 years ago
12

Chemical weathering is most rapid in areas that are

Physics
1 answer:
RUDIKE [14]3 years ago
8 0
Chemical weathering is most rapid in such areas that are warm in temperature. Basically, these are places that experience tropical weather. This is because places with tropical weather experience the most precipitation, which is an essential process in chemical weathering.
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A straight, nonconducting plastic wire 9.50 cm long carries a charge density of 130 nC/m distributed uniformly along its length.
Leviafan [203]

Answer:

A) E = 3.70*10^{4} N/C

B)  E = 2.281*10^3 N/C

Explanation:

given data:

charge density \lambda = 130*10^{-9} C/m

length of wire = 9.50 cm

a) at x  = 4.5 m above midpoint, electric field is calculated as

E = \frac{1}{ 2\pi \epsilon} * \frac{ \lambda}{x\sqrt{(x^2/a^2)+1}}

x = 4.5 cm

midpoint a = 4.5 cm = 0.0475 m

E =2{\frac{1}{ 8.99*10^9} * \frac{130*10^{-9} }{0.045\sqrt{(4.5^2/4.75^2)+1}}

E = 3.70*10^{4} N/C

B) when wire is in circle form

Q = \lambda * L

= 130*10^{-9} *9.5*10^{-2}

   = 1.235*10^{-8} C

Radius of circle

r = \frac{L}{2\pi}

r = \frac{9.5*10^{-2}}{2\pi}

r = 1.511*10^{-2} m

E = \frac{1}{ 2\pi \epsilon} * \frac{Qx}{(x^2+r^2)^{3/2}}

E =8.99*10^{9} * \frac{1.23*10^{-8}*4.5*10^{-2}}{((4.5*10^{-2})^2+(1.511*10^{-2})^2)^{3/2}}

E = 2.281*10^3 N/C

6 0
3 years ago
IPDE stands for ____________. A. Identify, Predict, Decide, and Execute B. Interpret, Predict, Divide, and Execute C. Identify,
Arturiano [62]
<span>d.Identify Predict Decide Execute hope this helps:)</span>
5 0
3 years ago
Read 2 more answers
"An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k
Sophie [7]

Answer:

the acceleration due to gravity, g of the cylinder is 9.81m/s2

Explanation:

since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2

5 0
3 years ago
T.E = K.E + P.E
Rasek [7]

Answer:

T.E=K.E+P.E

:146,000J=81250J+K.E

4 0
3 years ago
Two points are given in polar coordinates by : (r, θ) = (2.60 m, 50.0°)
alukav5142 [94]

Answer:

The distance between the 2 points is 4.6558 meters.

Explanation:

The distance between 2 points (r_1,\theta _1),(r_2,\theta _2) is given by

d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}

In our case the given 2 points are (2.60,50.0^{o}),(3.60,-46.0^{o}) hence the distance is

d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m

5 0
3 years ago
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