(4÷y+2) +(2÷y-3) =(6÷y+6)

1 answer:

3 0

<span>Simplifying 4(y + -3) = 6(y + 2) Reorder the terms: 4(-3 + y) = 6(y + 2) (-3 * 4 + y * 4) = 6(y + 2) (-12 + 4y) = 6(y + 2) Reorder the terms: -12 + 4y = 6(2 + y) -12 + 4y = (2 * 6 + y * 6) -12 + 4y = (12 + 6y) Solving -12 + 4y = 12 + 6y Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-6y' to each side of the equation. -12 + 4y + -6y = 12 + 6y + -6y Combine like terms: 4y + -6y = -2y -12 + -2y = 12 + 6y + -6y Combine like terms: 6y + -6y = 0 -12 + -2y = 12 + 0 -12 + -2y = 12 Add '12' to each side of the equation. -12 + 12 + -2y = 12 + 12 Combine like terms: -12 + 12 = 0 0 + -2y = 12 + 12 -2y = 12 + 12 Combine like terms: 12 + 12 = 24 -2y = 24 Divide each side by '-2'. y = -12 Simplifying y = -12</span>

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Y=(x-4)/(x*x)-11x+28

klio [65]

Y=(x-4)/2x-11x+28
y=(x/2x)-(4/2x)-11x+28
y=0.5x-2x-11x-28
1. subtract like terms
2. add 28 on both sides
3. so on and so forth...

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3 years ago

Construct a truth table for the statement: (p v q) v (~p ^ q) -> q

Gnom [1K]

Step-by-step explanation:

We have the following statement $(p\lor q)\lor(\lnot p \land q) \rightarrow q$

A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

The simple statements from the statement given are:

$\lnot p$ , $p\lor q$ , $\lnot p \land q$ , and $(p\lor q)\lor(\lnot p \land q)$