(4÷y+2) +(2÷y-3) =(6÷y+6)

1 answer:

3 0

<span>Simplifying 4(y + -3) = 6(y + 2) Reorder the terms: 4(-3 + y) = 6(y + 2) (-3 * 4 + y * 4) = 6(y + 2) (-12 + 4y) = 6(y + 2) Reorder the terms: -12 + 4y = 6(2 + y) -12 + 4y = (2 * 6 + y * 6) -12 + 4y = (12 + 6y) Solving -12 + 4y = 12 + 6y Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-6y' to each side of the equation. -12 + 4y + -6y = 12 + 6y + -6y Combine like terms: 4y + -6y = -2y -12 + -2y = 12 + 6y + -6y Combine like terms: 6y + -6y = 0 -12 + -2y = 12 + 0 -12 + -2y = 12 Add '12' to each side of the equation. -12 + 12 + -2y = 12 + 12 Combine like terms: -12 + 12 = 0 0 + -2y = 12 + 12 -2y = 12 + 12 Combine like terms: 12 + 12 = 24 -2y = 24 Divide each side by '-2'. y = -12 Simplifying y = -12</span>

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Write a linear function f with f(−10)=4 and f(−2)=4. f(x)=

ZanzabumX [31]

Answer:

f(x) = 4

Step-by-step explanation:

Let us assume that the linear function f(x) = ax + b

Here, we have to find the value of a and b to know the function.

Given that f(-10) = 4 and f(-2) = 4

So, -10a + b = 4 ....... (1) and

-2a + b = 4 .......... (2)

From equations (1) and (2) we get a = 0 and b = 4.