Need help with this question please.
1 answer:
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Based on the docx you showed me, the equation for the parabola is 
and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).
If you use these two points to create a line we get the equation:
(I just used point slope form)
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
and the x-intercept: 
.
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
If you use these two points to create a line we get the equation:
This can be simplified to:
Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept:
So our table of value can be:
x | y
______|________
-2 | 34
0 | 242 / 7
5 | 6
121/20 | 0
4f=2500 because 4 trips from 2500 means 
.