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SSSSS [86.1K]
3 years ago
5

What value of x makes this equation true? 3( 1/2x+4)= 2x+2

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

3(1/2x +4) = 2x +2

Use distributive property by multiply 3 by each term on the left side:

3/2x + 12 = 2x + 2

Subtract 12 from both sides:

3/2x = 2x -10

Subtract 2x from both sides:

-1/2x = -10

Multiply both sides by -2:

x = 20

Answer: x = 20

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a local community college has 860 students. Of these 860 students, 220 ride bicycles. Write the number of bike riders as a fract
Zinaida [17]

Answer:

11/43

Step-by-step explanation:

A local community college has 860 students

Out of this 860 students, 220students ride bikes

Therefore the fraction of bike riders to the number of students can be calculated as follows

= 220/860

= 11/43

4 0
2 years ago
This your time brubru 2+2=4-1=x<br> what is x?
Ira Lisetskai [31]

the answer is three look where it says 4-1 is 3

6 0
3 years ago
Read 2 more answers
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
How do I do this? <br><br>f(a)=4a+5; Find f(2)
Mariana [72]
F(2)=4(2)+5
f(2)=8+5
f(2)=13
6 0
3 years ago
Find the median of the data
nadya68 [22]
The median is the middle number of the data plot. Since there 30 numbers, there isn't a exact middle. To find the median you must add the two middle number then divide by 2. 

In this case you must add 87 and 88 which gives 175.

Then divide 175 by 2 which gives 87.5

87.5 is the median
5 0
3 years ago
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