Answer: large values of one variable are associated with small values of the other
Step-by-step explanation:
Answer:
Salena's got to the library first
Step-by-step explanation:
12½ miles = 25/2 miles
2½ miles = 5/2 miles
5¾ miles = 23/4 miles
114 miles = 114 miles
Salena's time of arrival =
if 5/2 miles : 5 minutes
then 25/2 miles : ?
25/2 ÷ 5/2. × 5
25/2 × 2/5 × 5
25 minutes
Justin 's time of arrival=
if 23/4 miles : 12 minutes
25/2 miles : ?
25/2 ÷ 23/4 ×12
25/2 × 4/23 ×12
26 minutes approximately
Brandon 's time of arrival=
if 114 miles : 258 minutes
25/2 miles : ?
25/2 ÷114 ×258
25/2 × 1/114×258
25 × 1/57 × 258
113 minutes approximately
Answer:
10 and 16, x+(x+6)=26
Step-by-step explanation:
Michelle has an age we don't know, so we put her age as x.
Yogi is 6 years older than her, so her age is x+6
Michelle=x
Yogi=x+6
we know both their ages equal 26. so we set it up as
x+(x+6)=26
combining like terms we get
2x+6=26
subtract 6 from both sides
2x=20
divide both sides by 2
x=10
now that we have the value for x, we plug it into their original ages
Michelle is 10, because her age is just x.
Yogi is 16, because her age is x+6
Solving by substitution:
y = 4x - 3
2x + 7y = 41
Let us substitute the first equation y = 4x - 3 into the second.
2x + 7y = 41
2x + 7(y = 4x -3) = 41
2x + 7(4x -3) = 41
So that's the third option.
I hope this helps.
Answer:
sample 1: 75
sample 2: 86
Step-by-step explanation: