There is a thousand answer to this problem.
Let's do the simplest one here.
f(x) or y = x - 1
f(x) or y = x + 1
f(x) or y = -x
Wait, would this count as a solution? : See the second attachment
There are 479001600 different ways the first 12 letters of the alphabet can be arranged.
We can solve this problem using discriminant.
x^2-4x-12's discriminant is
(-4)^2-4*-12=16+48 which is clearly larger than 0
This means that it crosses over the axes 2 times.
In case you don't know what discriminant is, its in equation ax^2+bx+c
the discriminant is b^2-4ac.
If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.
Hope this helped at least a little bit :D
Answer:
x₁ = -4
x₂ = 3
Step-by-step explanation:
x²+ x + 12 = 0
x = {-1±√((1²)-(4*1*-12))} / (2*1)
x = {-1±√(1+48)} / 2
x = {-1±√49} / 2
x = {-1±7} / 2
x₁ = {-1-7} / 2 = -8/2 = -4
x₂ = {-1+7} / 2 = 6/2 = 3
Check:
x₁
-4² + (-4) - 12 = 0
16 - 4 - 12 = 0
x₂
3² + 3 - 12 = 0
9 + 3 - 12 = 0
Answer:
1a. 8
1b. AB & BC
1c. AC
2.
miles
3. NO
Step-by-step explanation:
1a. AC is your hypotenuse which is C² and BC is B², so we plug it in the equation.
A²+6²=10²
A²+36=100
A²=64
A=
A=8
1b. Legs are the two shorter sides, AB & BC, which are 6 & 8 respectively.
1c. The hypotenuse is the longest side AC
2. Make lines that make the graph for a triangle with a line. My graph is linked below. Then counts the points, AC=6, BC=4, then use the pythagorean therom.
6²+4²=X²
36+16=52
=X
3. 15²+17²=19²
514=361
not possible
so it is not a right triangle