The ardor determines the result of a reaction.
[formula A]+[formula B]—> [formula C]
Here, the arrow signifies that when adding formula A and B, you get formula C. An arrow can also go both directions.
[formulaA]+[form.B]<—>[formulaC]+[form.D]
Here, the double sided arrows means that adding formulas A and B will give you C and D, and adding formulas C and D will give you A and B.
Answer:
<h2>Tt will take 4.04 seconds</h2>
Explanation:
In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken
Given that
final velocity= 3.4m/s
initia velocity u= 0m/s
deceleration= 0.84 m/s^2
time t= ?
applying
v=u+at
Substituting our given data into the expression above we have
3.4=0+0.84t
3.4=0.84t
divide both sides by 0.84 we have
3.4/0.84= t
t= 4.04 seconds
<h2>RED!</h2><h3></h3><h3>On the visible spectrum, red has the lowest frequency.</h3><h3>(I'm an amateur astronomer, so I would know.)</h3>
Answer:
the voltage across the resistor is V= 0
Explanation:
The correct answer is zero.
The answer is zero because the inductor acts as open circuit.
![i= i_0[1-e^{-\frac{t}{\tau} }]](https://tex.z-dn.net/?f=i%3D%20i_0%5B1-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D%5D)
i_o= maximum current
\tau= L/R= time constant
i= current at any instant
![V= V_0[1-e^{-\frac{t}{\tau} }]](https://tex.z-dn.net/?f=V%3D%20V_0%5B1-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D%5D)
at t=0 at the moment when contact is made
V=V_o[1-1]
⇒V= 0 V
assume the east-west direction along the x-axis such that east lies in positive x-direction and west lie in negative Y-direction.
In unit-vector notation , individual displacement can be represented as
A = displacement of car in east direction = 60 i
B = displacement of car in west direction = - 90 i
D = total displacement of the car
Total displacement of the car is given as
D = A + B
inserting the values
D = 60 i + (- 90 i)
D = - 30 i
negative sign indicates the direction in west
hence net displacement is 30 km in west direction
