Speed of the roller coaster at the top of the loop= 7.67 m/s
Explanation:
using the law of conservation of energy
KEi + PEi= KEf + PEf
KEi= kinetic energy at the top of the hill=0 because the car is at rest there.
PEi= potential energy at the top of the hill
PEf= potential energy at the top of the loop
KEf= kinetic energy at the top of the loop
Also kinetic energy= 1/ 2m v² and potential energy= mgh
m= mass
h= height
v= velocity
so 0+ mghi = 1/2mv² + mg h
500 (9.8)(10)+ 1/2 (500) v²= 500 ( 9.8) (7)
49000+250 v²= 34300
250v²= 14700
v²=58.8
v=7.67 m/s
Answer:
55.28 m
Explanation:
Mass of the rocket = 950 g = 950 / 1000 = 0.95 kg
force of gravity = 0.95 Kg × 9.81 m/s² = 9.3195 N
force due to acceleration = 18.3 N - 9.3195 N = 8.9805 N
F = ma
acceleration of the rocket = F / m = 8.9805 N / 0.95 Kg = 9.45 m/s²
using the equation of motion
d = ut + 1/2 at² u = 0 m/s
d = 1/2 at²
t = √(2d / a) = √ ( 2 × 40 m / 9.45 m/s²) = 2.91 s
the horizontal distance between the target and the rocket = vt = 19 m/s × 2.91 s = 55.28 m
Answer:
The answer is below
Explanation:
a) Given that the modulus of elasticity (E) = 317 GPa, to find the modulus of elasticity (in GPa) for the nonporous material (
), we use the formula:
b) If the porosity P = 11.1%, then the modulus of elasticity is:
It's true charged particles are always acted on by an electric field.when the velocity of the electron is parallel to the magnetic field, the magnetic force vanishes.
The vertical accelerations of the point a and point c are equal. because the vertical acceleration is due to the acceleration due to gravity. Acceleration due to gravity<span> may refer to: Gravitational acceleration, the acceleration caused by the gravitational attraction of massive bodies in general, which is equal to 9.8 m/s^2</span>
