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SIZIF [17.4K]
3 years ago
8

One side of a kite is 8 cm less than four times the length of another side. The perimeter of the kite is 78 cm. Find the lengths

of the sides of the kite
Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

9.4\:\mathrm{cm},\\9.4\:\mathrm{cm},\\29.6\:\mathrm{cm},\\29.6\:\mathrm{cm}

Step-by-step explanation:

A kite consists of two pairs of congruent adjacent sides. Therefore, we have the following equation:

2x+2(4x-8)=78, where x is the length of the shorter sides.

Solving, we get:

2x+8x-16=78,\\10x=94,\\x=\fbox{$9.4\:\mathrm{cm}$}.

Plugging in x=9.4 into 4x-8, we get:

4(9.4)-8,\\37.6-8,\\\fbox{$29.6\:\mathrm{cm}$}.

Therefore, two sides have length 9.4\:\mathrm{cm} and two sides have length 29.6\:\mathrm{cm}.

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Answer:

x=2

Step-by-step explanation:

3x^2=12 divide both sides by three

x^2=4 now find the square root of both sides

x=2

3 0
3 years ago
Find the area of the L shape.<br>9 cm<br>8 cm<br>3 cm<br>20 cm​
AfilCa [17]

Answer:

Step-by-step explanation:

(9*20)-(8*6) = 132 sq cm

5 0
3 years ago
Identify the initial amount a and the growth factor b in the exponential function. f(x) = 620 • 7.8x
Ivanshal [37]
The given is f(x) = 620 · 7.8x

The standard equation for an exponential function is f(x) = Aoe^bx

where:
A is the initial amount
b is the growth factor which is constant
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Therefore, the initial amount is 620 and the growth factor is 7.8
8 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

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Answer:

1/3

Step-by-step explanation:


7 0
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