Question

A car rental firm has 410 cars. Sixty-five of these cars have defective turn signals and 35 have defective tires. (Enter your probabilities as fractions.)
(a) What is the probability that one of these cars selected at random does not have defective turn signals?
(b) What is the probability that one of these cars selected at random has no defects if no car has 2 defects?

Answer 1

Answer:

(a)

Number of cars with defective turn signals = 65

Number of cars with no defective turn signals = 410 - 65 = 345

Required probability:

• P = 345/410*100% ≈ 84.15%

(b)

Number of cars with defects = 65 + 35 = 100

Number of cars with no defects = 410 - 100 = 310

Required probability:

• P = 310/410*100% ≈ 75.61%