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Vlad [161]
3 years ago
10

What determines the speed at which a particle of matter moves

Chemistry
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

The force exerted on it.

Explanation:

As the law of motion states, an object at rest will remain at rest an object in motion will remain in motion unless acted upon by another force.

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A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
USPshnik [31]

Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

Learn more about Partial pressure here:

brainly.com/question/15302032

#SPJ4

6 0
2 years ago
Identify the oxidizing agent in the reaction: sn(s) + 2h+(aq) → sn2+(aq) + h2(g)
mylen [45]
In the reaction Sn(s) + 2H+(aq) → Sn2+ (aq) + H2(g)
from this reaction, we get that Sn loses from 0 to 2 electrons so it's oxidized So it is the reducing agent.
and H  gains from 0 to 1 electrons so, it's reduced so ∴ it is the oxidizing agent
6 0
3 years ago
Read 2 more answers
Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
Nitella [24]

Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0
3 years ago
Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidi
valina [46]
(H+)(OH-) = Kw
kw=  1 x10^-14
OH-=  1   x10 ^-11
(H+)=  KW / OH-

concentration   of H+  = (1x10^-14) /.(1  x 10 ^-11)   =  1  x10  ^-3

Ph=  -log (H+)

PH=-log (  1  x  10  ^-3)  =  3  therefore  the    solution  is  acidic  since  the  PH   less than  7

7 0
3 years ago
Why are weight and mass used synonymously on Earth?
RUDIKE [14]
Actually mass and weight are two different things but most people did not understand the difference between them. And they are used synonymously on the earth. Mass is the measure of the amount of matter and weight is the measure of how the force of gravity acts on the mass that is Weight = mass x force of gravity. And they are also directly proportional to each other that is also the reason both terms are used synonymously.

5 0
3 years ago
Read 2 more answers
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