Answer:
2450 mg
Explanation:
From the given information:
The total weight of the capsule = 12.5 mg + 37.5 mg
= 50 mg
The percentage of drug in each capsule = ![\dfrac{12.5}{50} \times 100](https://tex.z-dn.net/?f=%5Cdfrac%7B12.5%7D%7B50%7D%20%5Ctimes%20100)
= 25%
= 0.25
To make 0.5 mg of drug in each 100 mg of powder after dilution;
Then, the drug percent in each capsule after dilution is:
![=\dfrac{0.5}{100}\times 100](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B0.5%7D%7B100%7D%5Ctimes%20100)
= 0.5%
= 0.005
Suppose (p) mg represent the amount that is added to the diluent in the given capsule. Then;
The total amount is = (50 + p) mg
Since the amount of the drug = 12.5 mg
Then the concentration
which needs to be equal to the needed concentration that is diluted.
i.e.
![\dfrac{12.5}{50 + x} = 0.005](https://tex.z-dn.net/?f=%5Cdfrac%7B12.5%7D%7B50%20%2B%20x%7D%20%3D%200.005)
By cross multiply;
(50 + x) 0.005 = 12.5
(50 × 0.005) + (0.005x) = 12.5
0.25 + 0.005x = 12.5
0.005x = 12.5 - 0.25
0.005x = 12.25
x = 12.25 / 0.005
x = 2450 mg
Thus, there is a need for an additional 2450 mg to make a dilution that compass 0.5 mg of drug in 100 mg powder.
Answer:
How is an environment able to support different varieties of organisms? ... It provides all the necessary conditions, such as temperature, space, water and food resources, oxygen and carbon dioxide, that suit the needs of the organisms. Examples of habitat include forests, mountains, bodies of water, and even puddles.
Explanation:
Answer:
12 grams and I have to write something longer so just ignore this
Mass water = 100 g solution - 10.5 g glucose => 89.5 g of H2O
Molar mass glucose => 180.1559 g/mol
Molality = moles glucose / kg solvent
( 10.5 / 180.1559 ) mol / ( 89.5 / 1000 ) kg =
0.0582 / 0.0895 => 0.650 mol/kg
hope this helps!
Answer:
2KOH + H2SO4 > K2SO4 + 2H2O
Explanation:
firstly the order speaks, you can't have something like OKOH so the other two is eliminated. Then check if the remaining reactions balance