Find the measure of the numbered angle. m∠2=

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
  </span> $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
   $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since,   $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
   $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since,   $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

4 years ago

Read 2 more answers

What happens when an atom of sulfur combines with two atoms of chlorine to produce SCI2?

Aloiza [94]

Answer:..A.) Each chlorine atom shares a pair of electrons with the sulfur atom

3 0

2 years ago

A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section

Sophie [7]

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

#SPJ1

6 0

2 years ago

In clinical applications, the unit parts per million (ppm) is used to express very small concentrations of solute, where 1 ppm i

Norma-Jean [14]

Answer: 25 μg of calcium in a total volume of 57 mL to ppm is 0.4386ppm

Explanation:

Please see the attachments below

3 0

3 years ago

When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni

VARVARA [1.3K]

Answer:

3.0 L of NH₃

Solution:

The equation is as follow,

N₂ + 3 H₂ → 2 NH₃

According to equation,

67.2 L (3 mole) H₂ at STP produces = 44.8 L (3 mole) of NH₃

So,

4.50 L of H₂ will produce = X L of NH₃

Solving for X,

X = (4.50 L × 44.8 L) ÷ 67.2 L

X = 3.0 L of NH₃

5 0

3 years ago

Find the measure of the numbered angle. m∠2= _