Using proportions, it is found that there is a 0.54 = 54% probability that a randomly selected household owns a cat.
<h3>What is a proportion?</h3>
A proportion is a fraction of total amount.
In this problem, the proportions associated with owning a cat are given by:
- 70% of 60%(also have a dog).
- 30% of 40%(do not have a dog).
Hence:
p = 0.7(0.6) + 0.3(0.4) = 0.42 + 0.12 = 0.54.
0.54 = 54% probability that a randomly selected household owns a cat.
More can be learned about proportions at brainly.com/question/24372153
Answer:
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Step-by-step explanation:
Wow a lot of plants but make a Mendelson Square [looks like a tic- tac -toe board (# this super large) with p and w at the top and p and w down the side. I would some how get those numbers checked out cuz generally there are only 4 squares:)
Answer:
adult $8.00
child $5.50
Step-by-step explanation:
Let the price of 1 adult ticket = x.
Let the price of 1 child ticket = y.
2x + 4y = 38
3x + 3y = 40.5
Multiply the first equation by 3. Multiply the second equation by -2. Then add them.
6x + 12y = 114
(+) -6x - 6y = -81
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6y = 33
y = 33/6
y = 5.5
2x + 4y = 38
2x + 4(5.5) = 38
2x + 22 = 38
2x = 16
x = 8
Answer:
adult $8.00
child $5.50
