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gogolik [260]
3 years ago
12

What is the period, in seconds, of the simple harmonic motion described by the equation x = 5sin(8πt)?

Mathematics
2 answers:
Zolol [24]3 years ago
5 0
\bf \qquad \qquad \qquad \qquad \textit{function transformations}

\bf \begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

now, let's see your equation  \bf \begin{array}{llccclll}
x=&5sin(&8\pi t&+0)&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\qquad period\implies \cfrac{2\pi }{B}\iff \cfrac{2\pi }{8\pi }
mart [117]3 years ago
3 0

<span>t=0.007958x
</span>
Hope that helps!

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find the area and perimeter using the lengthy and with step by step I will give 40 points please answer right number 6,7,9,10,11
N76 [4]

Answer:

6. 16 meters^2, 16 meters

7. 100 milimieters^2, 40 milimeters

9. 56 centimeters^2, 30 centimeters

10. 49 inches^2, 28 inches

11. 9 meters^2, 12 meters

12. 72 yards^2, 36 yards

Step-by-step explanation:

s is for a square

A=s^2

P=4s

l+w is for a rectangle

A=lw

P=2l+2w

6. A=4^2

A= 16 meters^2

P=4*4

P= 16 meters

7. A=10^2

A=100 milimieters^2

P=4*10

P= 40 milimeters

9. A=8*7

A= 56 centimeters^2

P=2(8)+2(7)

P=30 centimeters

10. A=7^2

A=49 inches^2

P=4*7

P=28 inches

11. A= 3^2

A=9 meters^2

P=4*3

P= 12 meters

12.

A=12*6

A=72 yards^2

P= 2(12)+2(6)

P= 36 yards

Let me know if you have any questions. Also, don't forget units!

4 0
2 years ago
-mapnwea.org growth/#/test-player
Aneli [31]

Answer: A and C and D and E

Step-by-step explanation:

I got this Q actually

5 0
3 years ago
Read 2 more answers
The height of a square pyramid-shaped gift box is one half the length of
Schach [20]

Answer:

15 inches

Step-by-step explanation:

Volume of a squre based pyramid :

V = a²(h/3)

a = base edge ; h = height

h =1/2 a

V = 4500

4500 = a² * (1/2a) ÷ 3

4500 = a² * a/2 * 1/3

4500 = a³/2 * 1/3

4500 = a³ / 6

27000 = a³

27000 = a³

Take the cube root of both sides

(27000)⅓ = a

30 = a

Recall:

h = 1/2a

h = 1/2(30)

h = 15 inches

5 0
3 years ago
A=. B= 2.6 c=6.2 using Pythagorean Theron what is a?
Kryger [21]
Hello!
So you will use the Pythagorean Theron equation which is Asquare + bsquare=C square
Plug in what you are given to find the missing piece

A square+ (2.6)square= (6.2) square
Asquare+ 6.76= 38.44
(Subtract 6.76to both sides to isolate A)
Asquare= 31.68
(Take the square root of both sides to find out what A is)
A=5.628

6 0
3 years ago
Read 2 more answers
What is y=2x^2-12x+16 in vertex form
Natasha2012 [34]

Answer:

y = 2(x-3)^2 - 2

Step-by-step explanation:

y = 2x^2 - 12x + 16

y = 2(x^2 - 6x + 8)

y = 2(x^2 - 6x +8 +1 -1) you "complete the square" by bringing the last term (8) up to "half of the middle co-efficient squared". Middle co-efficient is -6, half is -3, squared is 9. To get from 8 to 9 you must add 1 (+1), but if you add 1 you must subtract 1 (-1) so that you don't change the overall value of inside the bracket


y = 2(x^2 - 6x +9) - 2 (bring the -1 outside of the brackets)

y = 2(x-3)^2 - 2

3 0
2 years ago
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