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Sedaia [141]
2 years ago
11

Question 7

Mathematics
1 answer:
Pani-rosa [81]2 years ago
3 0
The answer should be 56
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An airplane takes 4 hours to travel a distance of 2600 miles with the wind. The return trip takes 5 hours against the wind. Find
tankabanditka [31]
2,600/4 =650
650•5 =3,250


I found the unit rate of the 2,600 by dividing the per hour and then times it by the 5 hours

Hopefully that was what you were looking for
3 0
3 years ago
Am I correct? Please explain!<br><br> Will mark brainliest
marta [7]

Answer:

nr. 1 and 3 is a Dilation 2 and 4 are not Dilations

Step-by-step explanation:

Dilation is an elnargment or shink of a figure by a x(factor) that makes the SAME image but smaller or larger

4 0
3 years ago
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
which number does NOT represent a whole number. a. 25. b. 13. c. 150 over3. d. 6.2
nikitadnepr [17]
6.2 is not a whole number


150/3 = 50 = a whole number
25 and 13 are whole numbers.
6 0
3 years ago
Simplify the expression 7x-1+2x
Leokris [45]

Answer:-23

Step-by-step explanation: i just know nika

6 0
2 years ago
Read 2 more answers
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