Answer:
The volume of the cylinder is 2520.64ft³
Step-by-step explanation:
To calculate the volume of a cylinder we have to use the following formula:
v = volume
h = height = 19ft
π = 3.14
r = radius = 6.5ft
v = (π * r²) * h
we replace with the known values
v = (3.14 * (6.5ft
)²) * 19ft
v = (3.14 * 42.25ft²) * 19ft
v = 132.665ft² * 19ft
v = 2520.64ft³
The volume of the cylinder is 2520.64ft³
The length of GH is 15.
<h3>How to calculate the length?</h3>
GH = IG
GH = 5x - 10
IG = 3x
5x - 10 = 3x
5x - 3x = 10
2x = 10
x = 10/2 = 5
GH = 5x - 10
= 5 * 5 - 10 = 25 - 10
GH = 15
<ABD = < DBC
<ABD = 10y°
<DBC = (8y + 4)°
10y° = (8y + 4)°
10y = 8y + 4
10y - 8y = 4
2y = 4
y = 4/2 = 2
The value of y is 2
<DBE = <DBC + <CBE
<DBC = 10y°
<CBE = <DBC = 10y°
y = 2
<DBC = <CBE = 10y° = 10*2° = 20°
<DBE = 20° + 20° = 40°
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V = 1,005.7 rounded off to one decimal place
Because:
Volume of a cylinder = πr²h
V = 22/7 x 4 x 4 x 20
V = 1,005.7
Answer:
The distance is (-4,3)
Step-by-step explanation:
count between the numbers :)
Step-by-step explanation:
1)
SA= 2 (Length x Breadth + breadth x height + Length x height)
SA= 2(2*5+5*6+6*2)=2(10+30+12)=104cm^2
2)
2(3*4+4*5+5*3)= 2(12+20+15)=94cm^2
3)
2(7*9+9*12+12*7)=2(63+108+84)= 510cm^2
4)
SA=
![A=2πrh+2π {r}^{2} [tex]A=2πrh+2π {r}^{2}](https://tex.z-dn.net/?f=A%3D2%CF%80rh%2B2%CF%80%20%7Br%7D%5E%7B2%7D%20%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%5Btex%5DA%3D2%CF%80rh%2B2%CF%80%20%7Br%7D%5E%7B2%7D%20)
= 2π 6*5+2π6*6= 188.495+226.194
SA= 414.689 cm^2
5)
2π7*4+2π*4*4=
SA=276.46 cm^2
6)
2π6*4+2π*4*4=
SA= 251.33 cm^2
7)
(3*4)/2=6
(3*4)/2=6
(3*8)=24
4*8=32
8*5=40
SA =6+6+24+32+40=108 cm^2
8)
(6*8)/2=24
(6*8)/2=24
6*12=72
8*12=96
10*12=120
SA= 24+24+72+96+120= 336 cm^2
9)
(5*12)/2=30
(5*12)/2=30
5*8=40
12*8=96
13*8=104
SA= 30+30+40+96+104= 300 cm^2