The combstion of ZnS in excess oxygen gives ZnO and SO₂ as the products.
hence the equation should be;
ZnS(s) + O₂(g) →ZnO(s) + SO₂(g)
At the left hand side: At the right hand side:
number of Zn atoms = 1 number of Zn atoms = 1
number of S atoms = 1 number of S atoms = 1
number of O atoms = 2 number of O atoms = 3
Hence the balanced equation is;
2ZnS(s) + 3O₂(g) →2ZnO(s) + 2SO₂(g)
When the substance is said to be an oxide of iron, that means the compound contains elements of Fe and O. Suppose you have 100 g of the sample.
Mass of Fe = 72.36 g
Mass of O = 100 - 72.36 = 27.64 g
The molar mass of Fe is 55.8 g/mol while the molar mass of O is 16 g/mol.
Moles of Fe = 72.36/55.8 = 1.29677
Moles of O = 27.64/16 = 1.7275
Now, divide both amounts by the lower number, which is 1.29677.
Fe: 1.29677/1.29677 = 1
O = 1.7275/1.29677 = 1.333
The answer must be whole numbers. So, let's try multiplying the least number to O that would make it a whole number. That would be 3.
Fe: 1*3 = 3
O: 1.333*3 = 4
<em>Thus, the empirical formula is Fe₃O₄.</em>
If I'm understanding the question correctly the answer would the proton to neutron ratio.
Answer:
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
75 % is decomposed which means that 0.75 of is decomposed. So,
= 1 - 0.75 = 0.25
t = 60 min
k = 0.023 min⁻¹
Considering the expression for half life as:-
Where, k is rate constant
So,
Answer:
Cs, Li, They can put Electrons into another element