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muminat
3 years ago
13

At a constant temperature, 600 mL of an ideal gas is at a pressure of 760 mmHg . If the volume is decreased to 300 mL, the press

ure of the gas will be
Chemistry
1 answer:
belka [17]3 years ago
7 0

Answer:

1520mmHg

Explanation:

Data obtained from the question include:

V1 (initial volume) = 600 mL

P1 (initial pressure) = 760 mmHg

V2 (final volume) = 300 mL

P2 (final pressure) =.?

Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:

P1V1 = P2V2

760 x 600 = P2 x 300

Divide both side by 300

P2 = (760 x 600) /300

P2 = 1520mmHg

The final pressure of the gas is 1520mmHg

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Aleks04 [339]

Answer:

The aquarium is covered and not in sunlight

Diminishing

Explanation:

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  • This food provides all other lives with energy through the break down of energy held in carbon chains.

Is the aquarium now in sunlight or is it covered?

Here is a feeding relationship between plants and fish in a pond. The producer here is the plants. The consumer is the fish.

Using carbon dioxide and water, plants manufactures food. When the amount of carbon starts decreasing it shows that the aquarium is covered.

The source of dissolved carbon dioxide in water is the fish which gives off this gas as it respires. When the fish ceases to respire, it does not have enough food and might have died thereby decreasing carbon dioxide levels.

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The energy levels in both plant and fish will begin to reduce because the plant is unable to produce food which the fish depends on.

This will furnish a rapid decline in the energy available in these living organisms since the plants are not able to produce.

7 0
3 years ago
Read 2 more answers
Which of the following is not a catalyst? A. Nickel B. Platinum C. Enzymes D. Phosphorus
Mazyrski [523]
The answer would be D because from my research it's the only one that didn't have a catalyst 
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3 years ago
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A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
How can you write tht in mg ??
inessss [21]
Rris is how u right it Mg=? Because it ask u a question and then you put the equal sign and then you put the question mark because you don't know it yet
3 0
3 years ago
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Oxygen freezes at -219°c and boils at -183°c in which state is oxygen at -200°c​
vova2212 [387]

oxygen is in gaseous state at this temperature

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3 years ago
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