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Paladinen [302]
3 years ago
7

Question 1 (1 point)

Chemistry
1 answer:
stealth61 [152]3 years ago
6 0

Answer:

Q1: 9

Q2:10

Q3: 50

Q4:True

Q5: False

Q6:False

Q7:True

Explanation: Just took the quiz

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Antimony has two naturally occuring isotopes, Sb121 and Sb123, Sb121 has an atomic mass of 120. 9038 u , and sb123 has an atomic
tino4ka555 [31]

Answer:

nah i dont feel like it

Explanation:

4 0
3 years ago
4Fe + 302 → 2Fe2O3
frez [133]

Answer:

2 -> O and Fe

Explanation:

5 0
3 years ago
Choices for images
BabaBlast [244]

One

Let's start by stating what we know is wrong. Equilibrium is achieved when the reactants and products have a stable concentration. That makes D incorrect. Equilibrium is not established until about the 6th or 7th second.

The fact that you get any products at all means that the reactants will become products.  Just who is favored has to be looked at very carefully. The products start very near 0. They go up until their concentration at equilibrium. When the reach equilibrium, the products have increased to 17. The reactants have dropped from 40 to 27. By a narrow margin, I would say the products are favored.

C is incorrect. There are still reactants left.  

E is incorrect. the reactants started out with a concentration of 40. The reaction is not instantaneous.  The concentration was highest at 40 or right at the beginning. This assumes that the reactants were mixed and the products were produced and the water/liquid amount has not changed.

B is incorrect. The concentration of the reactants is higher at equilibrium.

A is wrong. It is product favored.

I'm getting none of the above.

Problem Two

AgBr is insoluble (very). You'd have to work very hard to get them to separate into their elemental form. Just putting AgBr in water isn't enough. Lots of heat and lots of electricity are needed to get the elemental form.

I suppose you should pick B. Mass must be preserved. But if you balanced the equation, it would work with heat and electricity.



3 0
3 years ago
Read 2 more answers
A fuel was burned for 5 min, increasing the temperature of 10.0 g of water with a density of 1.00 g/ml by 9.0 oC. The fuel relea
jekas [21]

The fuel released 90 calories of heat.

Let suppose that water experiments an entirely <em>sensible</em> heating. Hence, the heat released by the fuel is equal to the heat <em>absorbed</em> by the water because of principle of energy conservation. The heat <em>released</em> by the fuel is expressed by the following formula:

Q = m\cdot c \cdot \Delta T (1)

Where:

  • m - Mass of the sample, in grams.
  • c - Specific heat of water, in calories per gram-degree Celsius.
  • \Delta T - Temperature change, in degrees Celsius.

If we know that m = 10\,g, c = 1\,\frac{cal}{g\cdot ^{\circ}C} and \Delta T = 9\,^{\circ}C, then the heat released by the fuel is:

Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)

The fuel released 90 calories of heat.

We kindly invite to check this question on sensible heat: brainly.com/question/11325154

7 0
2 years ago
8. which change in state is associated with the heat of vaporization,
rewona [7]
The answer is 2, liquid to vapor because vaporization is the process of liquids to vapors.
8 0
3 years ago
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