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2 years ago

Temperature (average kinetic energy) affects the density of a substance. True False

Chemistry

2 answers:

MrRa [10]2 years ago

4 0

Answer:

True

Explanation:

Higher temperature will have greater volumes so the density will be less.

Crazy boy [7]2 years ago

3 0

The answer is true!! i hope this helps!!!

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I need some help please

Norma-Jean [14]

Answer:

the first one to the third box

the second one to the fourth box

the third one to second box

and the fourth one to the first box

Explanation:

5 0

2 years ago

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O

madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9$ at 1,000 K

Calculate Kc for the reaction $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

<u>Answer:</u> The value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

<u>Explanation:</u>

The given chemical equations follows:

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c$

We need to calculate the equilibrium constant for the equation, which is:

$2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c'=(K_c)^2$

We are given:

$K_c=4.4\times 10^9$

Putting values in above equation, we get:

$K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}$

Hence, the value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

3 0

3 years ago

Identify the decomposition reaction. 2nh3 + h2so4 ⟶ (nh4)2so4 2nabr + ca(oh)2 ⟶ cabr2 + 2naoh 2 no2 ⟶ 2 o2 + n2 3pb + 2h3po4 ⟶ 3

TEA [102]

A decomposition reaction should look like

A ------> B +C+...

It has to have only one reactant and several products.

2 NO2 ⟶ 2 O2 + N2

7 0

3 years ago

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0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an

Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic , its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30 x 10⁻³ moles .

8 0

3 years ago

What happens when an island volcano erupts and molten lava flows out?

qwelly [4]

It will explode together cause danger

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3 years ago

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