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V= New mL displaced water - original old water that was already in the grad. cylinder basically 8.0 mL
Answer: Weather refers to short term atmospheric conditions while climate is the weather of a specific region averaged over a long period of time. Climate change refers to long-term changes.
Answer:
5.55 L
Explanation:
This excersise can be solved by the Boyle's law.
This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.
P₁ . V₁ = P₂ . V₂
The law comes from the Ideal Gases Law, in the first term.
P . V = n . R . T In this case, n . R . T are all constant.
6.35 L . 88.6 kPa = 101.3 kPa . V₂
V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa
V₂ = 5.55 L
It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.
Answer:
<em> = 0.2 mL.</em>
Explanation:
Given a 0.5 M solution of NaOH as stock solution, 10.0mL of 0.010M can be prepared via dilution with distilled water, by using the formula:
where C1 and V1 are initial concentration and volume respectively; same as C2 & V2 for fina.
Let C1 = 0.5M, V2 = ?
C2 = 0.010M; V2 = 10mL
⇒Volume of stock solution to be diluted, V2
= × 0.010
<em> = 0.2 mL.</em>
Glasswares used would be pipette (for smaller volume experiment) and measuring cylinder. 0.2mL would be measured and then made upto the 10mL mark of the measuring cylinder.
I hope this was a detailed explanation given the missing details of "Trial 1" in the question.