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Anna11 [10]
3 years ago
9

Which statement about protons is false?

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
6 0

<u>Answer:</u> The correct answer is Option 4.

<u>Explanation:</u>

There are three sub-atomic particles present in an atom. They are: electrons, protons and neutrons.

Protons constitute in each and every atom.

The charge on proton is of equal magnitude as that of electron but having opposite sign. Proton carry a positive charge and electron carry a negative charge.

Protons and neutrons, both determine the mass of an atom.

Mass of 1 proton = 1.007276 u

Mass of 1 neutron = 1.008664 u

Mass of 1 electron = 0.00054858 u

Mass of proton is almost same as that of neutron but is more than the mass of electron.

Hence, the correct answer is Option 4.

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Find the number of cations present in 7g of sodium prosphate Na=23 g/mol O=16g/mol P=31g/mol​
Snowcat [4.5K]

Answer:    This contains magnesium, Mg2+, and hydroxide, OH–

, ions. Each magnesium ion is +2 and

each hydroxide ion is -1: two -1 ions are needed for one +2 ion, and the formula for magnesium

hydroxide is Mg(OH)2. The (OH)2 indicates there are two OH–

ions. In a formula unit of

Mg(OH)2, there are one magnesium ion and two hydroxide ions; or one magnesium, two

oxygen, and two hydrogen atoms. The subscript multiplies everything in ( )

hope that helped!!

3 0
3 years ago
Does anyone know how to make this picture more clear so I can see the numbers?
bogdanovich [222]

Answer:

i dont know how.

Explanation:

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6 0
3 years ago
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
Help me please i need it for homework i cant seen to solve the answer :((
strojnjashka [21]
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7 0
3 years ago
You have added IgG-sensitized red cells to the negative indirect antiglobulin test result of the antibody screen procedure. You
Ivanshal [37]

Answer:

Positive

Explanation:

The antibody screen interpretation is positive. That's because of clump formation when antibody reacts with the antigen and agglutination occurs.

It means that the antibodies were present in the sample that react with the antigen present in the test tube.

5 0
3 years ago
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