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dolphi86 [110]
2 years ago
15

What is the slope of a line whose graph contains the points (−2,−6) and (0,0)?

Mathematics
1 answer:
torisob [31]2 years ago
4 0

Answer:

It’s D

Step-by-step explanation:

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Identify the rule that could possibly describe this set of data.
Elina [12.6K]

option D is the correct option

y= 10- 2x

Now, if we take the first value of x i.e 1

then, y= 10-2(1)

= 10-2 = 8 ---------> this value matches with the given value of y

take,x =2

y=10-2(2) = 10-4 = 6--------->this value matches with the given value of y

taking, x = 3

y= 10-2(3) = 10- 6=4-------->this value matches with the given value of y

7 0
3 years ago
Solve the following matrix equations: (matrices)
Masja [62]

Step-by-step explanation:

a)

3X + \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} = \begin{pmatrix}  - 1 & 6 \\ 10 & 14 \end{pmatrix} \\  \\  3X  = \begin{pmatrix}  - 1 & 6 \\ 10 & 14 \end{pmatrix} -  \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix}  \\  \\ 3X  = \begin{pmatrix}  - 1 - 2 & 6 - 3 \\ 10 - 4 & 14 - 5 \end{pmatrix}\\  \\ 3X  = \begin{pmatrix}   - 3 & 3 \\ 6 & 9\end{pmatrix}\\  \\ X  =  \frac{1}{3} \begin{pmatrix}   - 3 & 3 \\ 6 & 9\end{pmatrix}\\  \\ X  =  \begin{pmatrix}  \frac{ - 3}{3}  & \frac{3}{3}  \\  \\ \frac{6}{3}  & \frac{9}{3} \end{pmatrix}\\  \\ \huge \red{ X}  =  \purple{ \begin{pmatrix}  - 1  &1  \\ 2 & 3 \end{pmatrix}}

b)

3X + 2I_3=\begin{pmatrix} 5 & 0 & -3 \\6 & 5 & 0\\ 9 & 6 & 5\end{pmatrix} \\\\3X + 2\begin{pmatrix} 1 & 0 & 0\\ 0 & 1 & 0\\ 0 & 0 & 1\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\6 & 5 & 0\\ 9 & 6 & 5 \end{pmatrix} \\\\3X + \begin{pmatrix} 2 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 2\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} \\\\3X  =\begin{pmatrix} 5 & 0 & -3 \\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} - \begin{pmatrix} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{pmatrix} \\\\3X  =\begin{pmatrix} 5-2 & 0-0 & -3-0 \\ 6-0 & 5-2 & 0-0 \\ 9-0 & 6-0 & 5-2 \end{pmatrix} \\\\3X  =\begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X  =\frac{1}{3} \begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X  =\begin{pmatrix} \frac{3}{3}  & \frac{0}{3}  & \frac{-3}{3} \\\\ \frac{6}{3}  & \frac{3}{3}  & \frac{0}{3} \\\\ \frac{9}{3}  & \frac{6}{3}  & \frac{3}{3} \end{pmatrix} \\\\\huge\purple {X} =\orange{\begin{pmatrix} 1  & 0 & - 1\\ 2  & 1 & 0 \\ 3  & 2  & 1 \end{pmatrix}}\\

8 0
3 years ago
An artist is using right triangles in her design. If all the
katovenus [111]
I think it’s C because a triangle is 180 degrees and it’s a right triangle which means there is a 90 degrees angle + 30 degrees.
90+30=120. 180-120=60
Which means the third angle is 60 degrees
3 0
2 years ago
Read 2 more answers
Anyone who can answer this for me ill give 35 pts​
Andru [333]

Answer:

x^3+3x^2+4x+5

Step-by-step explanation:

Ok, so what helps me solve this kind of problem is to circle, underline, or box the like terms(the ones with the same exponent and variable). Be sure to note the sign of each term when combining like terms. take it one step at  a time, and work downwards starting with the highest exponent. You have -x^3 and +2x^3, which is x^3. Next, you have +2x^2 and +x^2, which is 3x^2. You should write down each of these as you go, so you should now have x^3+3x^2. Then combine the terms with no exponent but with x, which is 5x and -1x, which is +4x. You should have x^3+3x^2+4x now. Lastly, just combine the numbers 1, -1, and 5, which is 5. This gives you an answer of x^3+3x^2+4x+5.

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2 years ago
If you rotate the point (2, 3) 90 degrees counterclockwise about the origin, what is the image of the point?
AlexFokin [52]
Rotation counterclockwise 90 degrees has the rule

(x,y) -> (-y,x)

So the image is obtained, according to the rule, 
(2,3) -> (-3,2)
4 0
3 years ago
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