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Vladimir79 [104]
3 years ago
12

If something travels 4 meters in one second, what is its speed?

Physics
1 answer:
inna [77]3 years ago
8 0

Answer:

speed =distance /time

speed =4/1

speed 4m/s

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What do you mean ny speed?​
Brut [27]

Answer:

I think they mean it is really fast or fast paced

Explanation:

3 0
3 years ago
ou are to drive to an interview in another town, at a distance of 300 km on an expressway. The interview is at 11:15 a.m. You pl
Shkiper50 [21]

Answer:

133.62 kmh.

Explanation:

Time provided = 3.25 hours.

Distance to be covered 300 km

Times spent in first  100 km = 1 hour

Time spent in next 43 km

= 43 / 40 = 1.075 hours

Total time spent = 2.075 hours

Total distance covered = 143 km

Distance remaining = 300 - 143

=157 km .

Time remaining = 3.25 - 2.075

= 1.175

Speed required = Distance remaining / time remaining

= 157 / 1.175

= 133.62 kmh.

8 0
4 years ago
How are color and size related
DiKsa [7]
They’re both describing factors of something
5 0
4 years ago
Any example of acceleration related to human body??? <br> answer quickly plz :)
Hitman42 [59]

Answer:

Acceleration stress, physiological changes that occur in the human body in motion as a result of rapid increase of speed. ... A force of 3 g, for example, is equivalent to an acceleration three times that of a body falling near Earth.

4 0
3 years ago
A revolutionary war cannon, with a mass of 2090 kg, fires a 16.7 kg ball horizontally. The cannonball has a speed of 113 m/s aft
OLEGan [10]

Answer:

0.90291 m/s

0.45055 m/s

Explanation:

m_1 = Mass of canon = 2090 kg

m_2 = Mass of ball = 16.7 kg

v_1 = Velocity of canon

v_2 = Velocity of ball = 113 m/s

In this system the momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{16.7\times 113}{2090}\\\Rightarrow v_1=0.90291\ m/s

The velocity of the cannon is 0.90291 m/s

Applying energy conservation

\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_2^2=\dfrac{1}{2}m_2v^2\\\Rightarrow m_1v_1^2+m_2v_2^2=m_2v^2\\\Rightarrow v_2=\sqrt{\dfrac{m_1v_1^2+m_2v_2^2}{m_2}}\\\Rightarrow v_2=\sqrt{\dfrac{2090\times 0.90291^2+16.7\times 113^2}{16.7}}\\\Rightarrow v_2=113.45055\ m/s

The ball would travel 113.45055-113 = 0.45055 m/s faster

6 0
4 years ago
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