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Degger [83]
2 years ago
13

Any example of acceleration related to human body??? answer quickly plz :)

Physics
1 answer:
Hitman42 [59]2 years ago
4 0

Answer:

Acceleration stress, physiological changes that occur in the human body in motion as a result of rapid increase of speed. ... A force of 3 g, for example, is equivalent to an acceleration three times that of a body falling near Earth.

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There's more to motion than simply changing position. True Or False
prohojiy [21]

Answer: I think that it is False, if its wrong I am sorry.

Explanation:

8 0
2 years ago
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A gaseous sample of this element is bombarded by photons of various energies (in these same units). Match each photon to the res
solniwko [45]
1) n=1 -> n=2 : delta E = -5+11 = 6. The answer is D 
<span>2) n=1 -> n=3 : delta E = -2+11 = 9. The answer is B </span>
<span>3) n=1 -> n=4 : delta E = -1+11 = 10. No solution available </span>
<span>4) n=1 -> infinity delta E = 11. The answer is A </span>
<span>5) not absorbed would be C, as there is no transition with delta E of 8. </span>
8 0
3 years ago
 State how a ray of light can travel from air into glass without bending?
Katyanochek1 [597]

Answer:

If you shine a beam of light (a bundle of parallel rays) through the air, it will travel in a straight line. Rays of light usually travel in straight lines until they hit something. If a ray of light hits the surface of a sheet of glass, some light will be reflected by the surface of the glass.

Explanation:

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6 0
2 years ago
The closest distance a book can be read from a pair of reading eyeglasses (Power = 1.55 dp) is 26.0 cm. What is the near distanc
Mnenie [13.5K]

Answer:

The image distance is 20.0 cm.

Explanation:

Given that,

Power = 1.55 dp

Distance between book to eye = 26.0+3.00=29.0 cm

We need to calculate the focal length

Using formula of focal length

f = \dfrac{1}{P}

Put the value into the formula

f=\dfrac{1}{1.55}

f=0.645\ m

f=64.5\ cm

We need to calculate the image distance

Using lens formula

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{-u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{64.5}-\dfrac{1}{-29}

\dfrac{1}{v}=\dfrac{187}{3741}

v=20.0\ cm

Hence, The image distance is 20.0 cm.

5 0
3 years ago
If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?
Nina [5.8K]

The volume of rain that fells in the field is simply given by the area of the field, which is

A=100 mm^2

multiplied by the height of rain that fell, which is

h=5.0 mm

Therefore, the volume is

V=hA=(5 mm)(100 mm^2)=500 mm^3

7 0
3 years ago
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