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aev [14]
3 years ago
9

Ideally, when a thermometer is used to measure the temperature of an object, the temperature of the object itself should not cha

nge. However, if a significant amount of heat flows from the object to the thermometer, the temperature will change. A thermometer has a mass of 33.0 g, a specific heat capacity of c = 804 J/(kg C°), and a temperature of 15.4 °C. It is immersed in 149 g of water, and the final temperature of the water and thermometer is 56.0 °C. What was the temperature of the water in degrees Celsius before the insertion of the thermometer?
Physics
1 answer:
nordsb [41]3 years ago
5 0

Answer : The temperature of water is, 57.7^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of thermometer = 804J/kg.^oC=0.804J/g^oC

c_2 = specific heat of water = 4.18J/g.^oC

m_1 = mass of thermometer = 33.0 g

m_2 = mass of water = 149 g

T_f = final temperature = 56.0^oC

T_1 = initial temperature of thermometer = 15.4^oC

T_2 = initial temperature of water = ?

Now put all the given values in the above formula, we get:

33.0g\times 0.804J/g^oC\times (56.0-15.4)^oC=-149g\times 4.18J/g.^oC\times (56.0-T_2)^oC

T_2=57.7^oC

Therefore, the temperature of water is, 57.7^oC

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      sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

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we make the change of variable

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Let's find the displacement for this time

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In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

        x = 0.135 cm

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