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Svet_ta [14]
3 years ago
10

Find the area of the shaded region.

Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

3.315

Step-by-step explanation:

\frac{1}{2}  \times 1.7 \times 3.9 = 3.315

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6 times the sum of a number and 5 is 16
Taya2010 [7]
6(n+5)=16
Solve for n to get your answer
7 0
3 years ago
The length of a rectangle is 6 in longer than its width.if the perimeter of the rectangle is 68in find the length and width ?
wel

The length and the width of the rectangle are 20 and 14 inches respectively

<h3>How to find the length and width?</h3>

The given parameters are:

Length = 6 + Width

Perimeter = 68 inches

The perimeter of a rectangle is calculated as:

Perimeter = 2 * (Length + Width)

So, we have:

2 * (Length + Width) = 68

Divide both sides by 2

Length + Width = 34

Substitute Length = 6 + Width in Length + Width = 34

6 + Width + Width = 34

Evaluate the like terms

2 * Width = 28

Divide both sides by 2

Width = 14

Substitute Width = 14 in Length = 6 + Width

Length = 6 + 14

Evaluate

Length = 20

Hence, the length and the width of the rectangle are 20 and 14 inches respectively

Read more about perimeter at:

brainly.com/question/24571594

#SPJ1

6 0
1 year ago
Find the length of BC
bazaltina [42]

Answer:

BC = 19.78

Step-by-step explanation:

using sin(x) rule

sin(54)= 16/BC

sin(54)=0.80

∴0.80=16/BC  (divied both side by 0.80)

BC=16/0.80 =19.78

8 0
2 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
In parallelogram ABCD, the measure of angle ABC is 130, find the measure, in degrees of angle DAB
77julia77 [94]
Angle ABC = 130
Angle ABC = Angle ADC = 130 (Opposite angles are equal)
Angle DAB = 180 - 130 = 50 (consecutive interior angles)

I HOPE IT IS HELPFUL:D
6 0
3 years ago
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