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3 years ago

How many total atoms are in 0.720 g of p2o5

Chemistry

2 answers:

Katarina [22]3 years ago

5 0

Answer:

$4.92x10^{23}atoms,total$

Explanation:

Hello,

The following mole-mass relationship is applied to find the atoms of P and O, taking into account that the molar mass of P2O5 is 78g/mol:

$M_{P_2O_5}=31*2+16*5=78g/mol\\atoms_{P}=0.720gP_2O_5*\frac{1molP_2O_5}{78gP_2O_5} *\frac{2molP}{1molP_2O_5}*\frac{6.022x10^{23}atoms P}{1molP} =4.82x10^{22}atoms P\\atoms_{O}=0.720gP_2O_5*\frac{1molP_2O_5}{78gP_2O_5} *\frac{5molO}{1molP_2O_5}*\frac{6.022x10^{23}atoms O}{1molO} =1.2x10^{23}atoms O$

Now, by adding those atoms, one concludes:

$1.2x10^{23}atoms O+4.82x10^{22}atomsP=4.92x10^{23}atoms,total$

Best regards.

11Alexandr11 [23.1K]3 years ago

3 0

The total is 7 atoms in all

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$Let's~answer~your~question!$

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