Explanation:
<em>5</em><em>0</em><em>0</em><em> </em><em>degre</em><em>e</em><em> </em><em>Celsius</em><em> </em><em> </em><em>be</em><em>cause</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>see</em><em> </em><em>i</em><em>t</em><em> in</em><em> the</em><em> </em><em>tube</em>
This should help :)
Example 1: A 36.0 g sample of water is initially at 10.0 °C.
How much energy is required to turn it into steam at 200.0 °C? (This
example starts with a temperature change, then a phase change followed
by another temperature change.)
Solution:
<span>q = (36.0 g) (90.0 °C) (4.184 J g¯1 °C¯1) = 13,556 J = 13.556 kJ
q = (40.7 kJ/mol) (36.0 g / 18.0 g/mol) = 81.4 kJ
q = (36.0 g) (100.0 °C) (2.02 J g¯1 °C¯1) = 7272 J = 7.272 kJ
q = 102 kJ (rounded to the appropriate number of significant figures)
</span>
Answer:
yes as you wish
Explanation:
but why have u asked this
The answer for that is 16, math right?
Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?
Explanation: