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2 years ago

How many molecules of fructose would you have if you have 0.7 moles of fructose? *

Chemistry

1 answer:

iogann1982 [59]2 years ago

5 0

Answer:

4.214 × 10^23 molecules.

Explanation:

Number of molecules in a substance can be calculated by multiplying the number of moles in that substance by Avagadro's number, which is 6.02 × 10^23.

That is, no. of molecule = n × Avagadro constant

In this case, there are 0.7 moles of fructose. Hence;

number of molecules = 0.7 × 6.02 × 10^23

no. of molecule = 4.214 × 10^23 molecules.

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An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

Answer: The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

$\text{Molarity of salt}=\frac{0.050mol}{0.500L}\\\\\text{Molarity of salt}=0.1M$

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

We are given:

pH = 8.08

$pOH=14-8.08=5.92$

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

Putting values in above equation, we get:

$5.92=-\log[OH^-]$

$[OH^-]=10^{-5.92}=1.202\times 10^{-6}M$

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of $X^-$ ions follows:

$X^-(aq.)+H_2O(l)\rightleftharpoons HX(aq.)+OH^-(aq.);K_b$

Initial: 0.1

At eqllm: 0.1-x x x

Concentration of $OH^-=x=1.202\times 10^{-6}M$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[OH^-][HX]}{[X^-]}$

Putting values in above expression, we get:

$K_b=\frac{(1.202\times 10^{-6})\times (1.202\times 10^{-6})}{(1-(1.202\times 10^{-6}))}\\\\K_b=1.445\times 10^{-11}M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.445\times 10^{-11}$

Putting values in above equation, we get:

$10^{-14}=1.445\times 10^{-11}\times K_a\\\\K_a=\frac{10^{-14}}{1.445\times 10^{-11}}=6.92\times 10^{-4}$

We know that:

$K_a\text{ for HF}=6.8\times 10^{-6}$

$K_a\text{ for HCl}=1.3\times 10^{6}$

$K_a\text{ for HClO}=3.0\times 10^{-8}$

So, the calculated $K_a$ is approximately equal to the $K_a$ of HF

Hence, the unknown salt is NaF

6 0

3 years ago

Which option is an example of a chemical property?

Alona [7]

Answer:
The ability to decompose
Explanation:
A property is a chemical property when it changes the chemical structure of a substance after a reaction.
Density and color are both physical properties.
Even though melting point may seem like a chemical property, when something melts, only the physical state changes, and the chemical structure does not change, and therefore, is a physical property.
The ability to decompose is a chemical property. When something decomposes, the chemical structure of many molecules change, and therefore, is classified as a chemical property.

8 0

3 years ago

Read 2 more answers

How do we observe in experiments?

anyanavicka [17]

Answer:

by watching and writing down the information that is provided

Explanation:

6 0

3 years ago

How many nucleons are in an Iodine element? Okay

Lady_Fox [76]

Answer:

there are 74

Explanation:

3 0

2 years ago

How many grams of NO can be made from 50 g of NH3? 4 NH3 + 5 O2 → 6 H2O + 4 NO

Evgen [1.6K]

0.08 because 4mol NO divided by 50g gives you your answer

4 0

2 years ago