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3 years ago

The statement "if I raise the temperature of

Physics

2 answers:

masha68 [24]3 years ago

8 0

B is the answer for this here question

Doss [256]3 years ago

7 0

Answer:

B is the answers for the question

Explanation:

please give me brainlest

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The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a

likoan [24]

Answer:

14869817.395 m

Explanation:

$\theta$ =22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

$22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians$

From Rayleigh Criterion

$\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m$

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

7 0

3 years ago

If a gas is heated up， how does this affect the motion of its particles？

crimeas [40]

In gases, temperature relates to its kinetic energy — the hotter the gas, the faster the particles will move (for example, if we take that the formula of kinetic energy is Ek = 3/2 * k * T where k iz Boltzmanns constant and T is temperature, we see that kinetic energy — which is the energy an object has when its moving — only really depends on the temperature.)

7 0

3 years ago

A 0.017 g coin sliding to the right at 0.255 m/s makes an elastic head-on collision with a 0.040 g coin that is initially at res

zysi [14]

Answer:

$\approx 0.154\:\mathrm{m/s}$

Explanation:

In all collisions, whether elastic or inelastic, momentum must be conserved. Therefore, we can write an equation using the conservation of momentum:

$m_{c1}v_{c1,i}+m_{c2}v_{c2,i}=m_{c1}v_{c1,f}+m_{c2}v_{c2,f}$

Solving for $v_{2c,f}$ :

$0.000017\cdot 0.255+0.000040\cdot0=0.000017\cdot (-0.108)+0.000040\cdot v_{c2,f},\\v_{c2,f}\approx \boxed{0.154\:\mathrm{m/s}}$

*Notes:

-It's important to convert g to kg, as kg is the SI unit of mass

-The negative sign in a velocity measure represents direction

-Since the velocity we solved for is positive, it implies that the direction is to the right

5 0

3 years ago

How much work in joules must be done to stop a 920-kg car traveling at 90 km/h?

tankabanditka [31]

Answer:

Work done, W = −287500 Joules

Explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0

Work done is also defined as the change in kinetic energy of an object i.e.

$W=\Delta K$

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 920\ kg(0-(25\ m/s)^2)$

W = −287500 Joules

Negative sign shows the work done is done is opposite direction.

3 0

3 years ago

a stone is vertically thrown upward with the velocity of 72km/hr find the maximum height reached the height

erik [133]

Answer:

y = 20.38 [m]

Explanation:

In order to solve these problems, we must use the following kinematics equation.

$v_{f} ^{2} =v_{i} ^{2}-(2*g*y)$

where:

Vf = final velocity = 0

Vi = initial velocity = 72 [km/h]

g = gravity acceleration = 9.81 [m/s^2]

y = vertical elevation [m]

We need to convert [km/h] to [m/s]

$72[\frac{km}{h}]*[\frac{1h}{3600s}]*[\frac{1000m}{1km} ] = 20 [m/s]$

Note: the negative sign of the equation means that the acceleration acts in the opposite direction to the movement of the body. And the final speed is zero, because when the body reaches the maximum height, the Stone does not move its speed has been reduced to its entirety.

0 = (20)^2 - (2*9.81*y)

20^2 = 2*9.81*y

y = 20.38 [m]

3 0

3 years ago