Answer:
The depth and acceleration are 0.1919291 ft and 3.61 m/s².
Explanation:
Given that,
Density of block 
Density of fluid 
We need to calculate the depth
Using balance equation
....(I)
We know that,
The density is


Put the value of m in equation (I)



Put the value into the formula



We need to calculate the acceleration
Using formula of net force



....(II)
Put the value in the equation (II)


Hence, The depth and acceleration are 0.1919291 ft and 3.61 m/s².
It should be A sorry if I’m wrong
Answer:Time constant gets doubled
Explanation:
Given
L-R circuit is given and suppose R and L is the resistance and inductance of the circuit then current is given by
![i=i_0\left [ 1-e^{-\frac{t}{\tau }}\right ]](https://tex.z-dn.net/?f=i%3Di_0%5Cleft%20%5B%201-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%20%7D%7D%5Cright%20%5D)
where
is maximum current
i=current at any time


thus if inductance is doubled then time constant also gets doubled or twice to its original value.
Solution
distance travelled by Chris
\Delta t=\frac{1}{3600}hr.
X_{c}= [(\frac{21+0}{2})+(\frac{33+21}{2})+(\frac{55+47}{2})+(\frac{63+55}{2})+(\frac{70+63}{2})+(\frac{76+70}{2})+(\frac{82+76}{2})+(\frac{87+82}{2})+(\frac{91+87}{2})]\times\frac{1}{3600}
=\frac{579.5}{3600}=0.161miles
Kelly,
\Delta t=\frac{1}{3600}hr.
X_{k}=[(\frac{24+0}{2})+(\frac{3+24}{2})+(\frac{55+39}{2})+(\frac{62+55}{2})+(\frac{71+62}{2})+(\frac{79+71}{2})+(\frac{85+79}{2})+(\frac{85+92}{2})+(\frac{99+92}{2})+(\frac{103+99}{2})]\times\frac{1}{3600}
=\frac{657.5}{3600}
\Delta X=X_{k}-X_{C}=0.021miles