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slamgirl [31]
3 years ago
5

A metal sphere with radius R1 has a charge Q1. Take the electric potential to be zero at an infinite distance from the sphere.Ex

press your answer in terms of the given quantities and appropriate constants.1. What is the electric field at the surface of the sphere?E=2.What is the electric potential at the surface of the sphere?V=
Physics
1 answer:
amid [387]3 years ago
3 0

Answer:

E =   k*Q₁/R₁² V/m

V =  k*Q₁/R₁ Volt

Explanation:

Given:

- Charge distributed on the sphere is Q₁

- The radius of sphere is R₁

- The electric potential at infinity is 0

Find:

What is the electric field at the surface of the sphere?E.

What is the electric potential at the surface of the sphere?V

Solution:

- The 3 dimensional space around a charge(source) in which its effects is felt is known in the electric field.

- The strength at any point inside the electric field is defined by the force experienced by a unit positive charge placed at that point.  

- If a unit positive charge is placed at the surface it experiences a force according to the Coulomb law is given by

                                        F = k*Q₁/R₁²

- Then the electric field at that point is

                                        E =  F/1

                                        E =  k*Q₁/R₁²  V/m

- The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point against electric forces.

- Thus, the electric potential at the surface of the sphere of radius R₁ and charge distribution Q₁ is given by the relation

                                        V =  k*Q₁/R₁  Volt

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Answer:

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Explanation:

4 0
3 years ago
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Which is a form of kinetic energy?
Digiron [165]
The forms of kinetic energy are motion, heat, sound and light.

So according to your options, I choose D) Sound energy.
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Internal diameter of a test tube<br>​
sladkih [1.3K]

Answer:

16 mm with 14 mm inside diameter.

4 0
3 years ago
A strong lightning bolt transfers an electric charge of about 31 C to Earth (or vice versa). How many electrons are transferred?
olchik [2.2K]

Answer:

m=5.78\times 10^{-3}\ g

n_e=1.935\times 10^{20} is the no. of electrons

Explanation:

Given:

  • quantity of charge transferred, Q=31\ C

<u>No. of electrons in the given amount of charge:</u>

As we have charge on one electron 1.602\times 10^{-19}\ C

so,

n_e=\frac{Q}{e}

n_e=\frac{31}{1.602\times 10^{-19}}

n_e=1.935\times 10^{20} is the no. of electrons

  • Now if each water molecules donates one electron:

Then we require n=1.935\times 10^{20} molecules.

<u>Now the no. of moles in this many molecules:</u>

n_m=\frac{n}{N_A}

where

N_A=6.022\times 10^{23} Avogadro No.

n_m=\frac{1.935\times 10^{20}}{6.022\times 10^{23}}

n_m=3.213\times 10^{-4}\ moles

  • We have molecular mass of water as M=18 g/mol.

<u>So, the mass of water in the obtained moles:</u>

n_m=\frac{m}{M}

where:

m = mass in gram

3.213\times 10^{-4}=\frac{m}{18}

m=5.78\times 10^{-3}\ g

7 0
3 years ago
The IMA is always smaller than the AMA.<br><br> True<br> False
VMariaS [17]
Best answer must be false. Because the IMA it doesn't have always stay smaller than the AMA. Hope it helped you!
6 0
4 years ago
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