**Answer:**

E = k*Q₁/R₁² V/m

V = k*Q₁/R₁ Volt

**Explanation:**

**Given:**

- Charge distributed on the sphere is Q₁

- The radius of sphere is R₁

- The electric potential at infinity is 0

**Find:**

What is the electric field at the surface of the sphere?E.

What is the electric potential at the surface of the sphere?V

**Solution:**

- The 3 dimensional space around a charge(source) in which its effects is felt is known in the electric field.

- The strength at any point inside the electric field is defined by the force experienced by a unit positive charge placed at that point.

- If a unit positive charge is placed at the surface it experiences a force according to the Coulomb law is given by

F = k*Q₁/R₁²

- Then the electric field at that point is

E = F/1

** E = k*Q₁/R₁² V/m**

- The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point against electric forces.

- Thus, the electric potential at the surface of the sphere of radius R₁ and charge distribution Q₁ is given by the relation

**V = k*Q₁/R₁ Volt**