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JulsSmile [24]
2 years ago
14

Information about the age of participants in a robotics competition is in the image

Mathematics
2 answers:
r-ruslan [8.4K]2 years ago
5 0

I would say 11 and 16 but i think that the awnser could also be 13 and 33

Maru [420]2 years ago
3 0
11 and 33.............
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Tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha
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Answer: the maximum number of packets they can make i 4 packets to make the maximum number of packets, each packet should have 7 milk chocolates and 6 dark chocolates. If that does not work then there can be 2 packets with 14 milk chocolates and 12 dark chocolates.

Step-by-step explanation:

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3 integers less than 25 range of 10 mean of 13​
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Answer:

8, 13, 18

Step-by-step explanation:

If we want the mean to be 13, and there are 3 integers, that means the sum of all 3 integers must be 39. I started at 13 and counted 5 up and 5 down, which already makes sure of the range and the mean is 13 (since it's balanced with 13 being the middle), therefore, 13+5 is 18, 13-5=8.

6 0
3 years ago
A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re
Daniel [21]

From the equation of motion, we know,

s=ut+\frac{1}{2}at^{2}

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u= initial velocity

a= gravitational force

t= time

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A = -9.8m/s^{2} since the ball is thrown upwards.

Plug the known values into the equation.

=> 0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

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4 0
3 years ago
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
3 years ago
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